首页 > 代码库 > [ES7] Await multi promises sequentially or concurrently
[ES7] Await multi promises sequentially or concurrently
Somtime ‘async await‘ can have a bad effect on code proferemence. Let‘s take a look the below example:
const fetch = require(‘node-fetch‘);const BASE_URL = ‘https://api.github.com/users‘;class GithubUser { async fetchGitHubUser(handle) { const response = await fetch(`${BASE_URL}/${handle}`); const body = await response.json(); if (response.status !== 200) { throw Error(body.message); } return body; } async fetchGitHubRepos(handle) { const response = await fetch(`${BASE_URL}/${handle}/repos`); const body = await response.json(); if (response.status !== 200) { throw Error(body.message); } return body; }}(async () => { const github = new GithubUser(); try { const user = await github.fetchGitHubUser(‘zhentian-wan‘); const repos = await github.fetchGitHubRepos(‘zhentian-wan‘); console.log(user); console.log(repos); } catch(err) { console.error(err); }})();
In the example, we are doing two await operations sequentially:
const user = await github.fetchGitHubUser(‘zhentian-wan‘); const repos = await github.fetchGitHubRepos(‘zhentian-wan‘);
Remember that ‘await‘ will pause the JS execution until promise resolve or reject.
So if one api request cost 0.5s then two in sequence will cose 1s.
The way to solve the problem is by converting operations to concurrently:
const userPromise = github.fetchGitHubUser(‘zhentian-wan‘); const reposPromise = github.fetchGitHubRepos(‘zhentian-wan‘); const user = await userPromise; const repos = await reposPromise; console.log(user.name); console.log(repos.length);
Or we can use Promise.all:
const [user, repos] = await Promise.all([ github.fetchGitHubUser(‘zhentian-wan‘), github.fetchGitHubRepos(‘zhentian-wan‘) ]); console.log(user.name, repos.length);
Of course, tow approaches are not the same, Promise.all will throw error if one of the request throw error.
[ES7] Await multi promises sequentially or concurrently
声明:以上内容来自用户投稿及互联网公开渠道收集整理发布,本网站不拥有所有权,未作人工编辑处理,也不承担相关法律责任,若内容有误或涉及侵权可进行投诉: 投诉/举报 工作人员会在5个工作日内联系你,一经查实,本站将立刻删除涉嫌侵权内容。