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LeetCode ZigZag Conversion

2024-07-30 12:37:39   221人阅读

The string "PAYPALISHIRING" is written in a zigzag pattern on a given number of rows like this: (you may want to display this pattern in a fixed font for better legibility)

P   A   H   NA P L S I I GY   I   R

And then read line by line: "PAHNAPLSIIGYIR"

 

Write the code that will take a string and make this conversion given a number of rows:

string convert(string text, int nRows);

convert("PAYPALISHIRING", 3) should return "PAHNAPLSIIGYIR".

 

0   8   16   
1  79  1517   
2 6 10 14 18   
35  1113  19   
4   12   20   

 

分两次循环，第一次是列，第二次是斜线。

java需使用stringbuffer才不会超时，使用string超时了。

 1 public class Solution { 2     public String convert(String s, int nRows) { 3         if (nRows==1) { 4             return s; 5         } 6         7         StringBuffer[]    reBuffers=new StringBuffer[nRows]; 8         for (int i = 0; i < reBuffers.length; i++) { 9             reBuffers[i]=new StringBuffer();10         }11         int i=0,j=0,C=nRows-2;12         while (i<s.length()) {13             for (j = 0; j<nRows&&i<s.length() ;j++) {14         15                 reBuffers[j].append(s.charAt(i++));16                 17             }18             19             for (j = C; i<s.length()&&j>0;j--) {20                 21                 reBuffers[j].append(s.charAt(i++));22                 23             }24             25         }26         27         StringBuffer    res=new StringBuffer();28         for (int k = 0; k < nRows; k++) {29             res.append(reBuffers[k]);30         }31         return res.toString();32     }33 }

 

LeetCode ZigZag Conversion


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