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HDU 3718 Similarity(KM最大匹配)
HDU 3718 Similarity
题目链接
题意:给定一个标准答案字符串,然后下面每一行给一个串,要求把字符一种对应一种,要求匹配尽量多
思路:显然的KM最大匹配问题,位置对应的字符连边权值+1
代码:
#include <cstdio> #include <cstring> #include <cmath> #include <algorithm> using namespace std; const int MAXNODE = 27; typedef int Type; const Type INF = 0x3f3f3f3f; struct KM { int n, m; Type g[MAXNODE][MAXNODE]; Type Lx[MAXNODE], Ly[MAXNODE], slack[MAXNODE]; int left[MAXNODE], right[MAXNODE]; bool S[MAXNODE], T[MAXNODE]; void init(int n, int m) { this->n = n; this->m = m; memset(g, 0, sizeof(g)); } void add_Edge(int u, int v, Type val) { g[u][v] += val; } bool dfs(int i) { S[i] = true; for (int j = 0; j < m; j++) { if (T[j]) continue; Type tmp = Lx[i] + Ly[j] - g[i][j]; if (!tmp) { T[j] = true; if (left[j] == -1 || dfs(left[j])) { left[j] = i; right[i] = j; return true; } } else slack[j] = min(slack[j], tmp); } return false; } void update() { Type a = INF; for (int i = 0; i < m; i++) if (!T[i]) a = min(a, slack[i]); for (int i = 0; i < n; i++) if (S[i]) Lx[i] -= a; for (int i = 0; i < m; i++) if (T[i]) Ly[i] += a; } Type km() { memset(left, -1, sizeof(left)); memset(right, -1, sizeof(right)); memset(Ly, 0, sizeof(Ly)); for (int i = 0; i < n; i++) { Lx[i] = -INF; for (int j = 0; j < m; j++) Lx[i] = max(Lx[i], g[i][j]); } for (int i = 0; i < n; i++) { for (int j = 0; j < m; j++) slack[j] = INF; while (1) { memset(S, false, sizeof(S)); memset(T, false, sizeof(T)); if (dfs(i)) break; else update(); } } Type ans = 0; for (int i = 0; i < n; i++) { ans += g[i][right[i]]; } return ans; } } gao; const int N = 10005; int t, n, k, m; char s[N][2]; int main() { scanf("%d", &t); while (t--) { scanf("%d%d%d", &n, &k, &m); for (int i = 0; i < n; i++) scanf("%s", s[i]); while (m--) { gao.init(26, 26); char c[2]; for (int i = 0; i < n; i++) { scanf("%s", c); gao.add_Edge(s[i][0] - 'A', c[0] - 'A', 1); } printf("%.4lf\n", gao.km() * 1.0 / n); } } return 0; }
HDU 3718 Similarity(KM最大匹配)
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