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POJ 3237 Tree 树链剖分

单点替换,区间取相反数,区间求最大值,其实线段树里面只要保存最小值和最大值就可以了,取反之后最小值变成最大值最大值变成最小值。

#include <cstdio>#include <cstring>#include <algorithm>#include <map>#include <set>#include <bitset>#include <queue>#include <stack>#include <string>#include <iostream>#include <cmath>#include <climits>using namespace std;const int maxn = 10000 + 5;int n, head[maxn], nxt[maxn << 1], u[maxn << 1], v[maxn << 1], w[maxn << 1];int tid[maxn], maxson[maxn], fa[maxn], dep[maxn], siz[maxn], idcnt, ecnt;int top[maxn], maxv[maxn << 2], minv[maxn << 2], sval[maxn], lazy[maxn << 2];int eid[maxn << 1], rnum[maxn];#define lson rt << 1, l, mid#define rson rt << 1 | 1, mid + 1, rvoid init() {	memset(head, -1, sizeof(head));	memset(maxson, -1, sizeof(maxson));	ecnt = idcnt = 0;}void adde(int uu, int vv, int ww, int id) {	u[ecnt] = uu; v[ecnt] = vv; w[ecnt] = ww; eid[ecnt] = id;	nxt[ecnt] = head[uu]; head[uu] = ecnt++;}void dfs1(int now, int nowfa, int nowdep) {	fa[now] = nowfa; dep[now] = nowdep;	siz[now] = 1;	for(int i = head[now]; ~i; i = nxt[i]) if(v[i] != nowfa) {		dfs1(v[i], now, nowdep + 1);		siz[now] += siz[v[i]];		if(maxson[now] == -1 || siz[v[i]] > siz[maxson[now]]) {			maxson[now] = v[i];		}	}}void dfs2(int now, int tp) {	top[now] = tp;	tid[now] = ++idcnt;	if(maxson[now] == -1) return;	dfs2(maxson[now], tp);	for(int i = head[now]; ~i; i = nxt[i]) {		if(v[i] != fa[now] && v[i] != maxson[now]) {			dfs2(v[i], v[i]);		}	}}void pushup(int rt) {	minv[rt] = min(minv[rt << 1], minv[rt << 1 | 1]);	maxv[rt] = max(maxv[rt << 1], maxv[rt << 1 | 1]);}void pushdown(int rt) {	if(lazy[rt] == 0) return;	int lc = rt << 1, rc = rt << 1 | 1;	lazy[lc] ^= lazy[rt]; lazy[rc] ^= lazy[rt];	swap(minv[lc], maxv[lc]); swap(minv[rc], maxv[rc]);	minv[lc] = -minv[lc]; minv[rc] = -minv[rc];	maxv[lc] = -maxv[lc]; maxv[rc] = -maxv[rc];	lazy[rt] = 0;}void build(int rt, int l, int r) {	int mid = (l + r) >> 1;	lazy[rt] = 0;	if(l == r) {		minv[rt] = maxv[rt] = sval[l];	}	else {		build(lson); build(rson);		pushup(rt);	}}void change(int rt, int l, int r, int pos, int val) {	if(l == r) {		minv[rt] = maxv[rt] = val;	}	else {		int mid = (l + r) >> 1;		pushdown(rt);		if(pos <= mid) change(lson, pos, val);		else change(rson, pos, val);		pushup(rt);	}}void update(int rt, int l, int r, int ql, int qr) {	if(ql <= l && qr >= r) {		swap(minv[rt], maxv[rt]);		minv[rt] = -minv[rt]; maxv[rt] = -maxv[rt];		lazy[rt] ^= 1;	}	else {		int mid = (l + r) >> 1;		pushdown(rt);		if(ql <= mid) update(lson, ql, qr);		if(qr > mid) update(rson, ql, qr);		pushup(rt);	}}int query(int rt, int l, int r, int ql, int qr) {	if(ql <= l && qr >= r) return maxv[rt];	int mid = (l + r) >> 1, ret = -1e9;	pushdown(rt);	if(ql <= mid) ret = max(ret, query(lson, ql, qr));	if(qr > mid) ret = max(ret, query(rson, ql, qr));	pushup(rt);	return ret;}int ask(int x, int y) {	int ret = -1e9;	while(top[x] != top[y]) {		if(dep[top[x]] < dep[top[y]])			swap(x, y);		ret = max(ret, query(1, 1, idcnt, tid[top[x]], tid[x]));		x = fa[top[x]];	}	if(dep[x] > dep[y]) swap(x, y);	if(x != y) ret = max(ret, query(1, 1, idcnt, tid[x] + 1, tid[y]));	return ret;}void Negate(int x, int y) {	while(top[x] != top[y]) {		if(dep[top[x]] < dep[top[y]]) swap(x, y);		update(1, 1, idcnt, tid[top[x]], tid[x]);		x = fa[top[x]];	}	if(dep[x] > dep[y]) swap(x, y);	if(x != y) update(1, 1, idcnt, tid[x] + 1, tid[y]);}void debug() {	for(int i = 1; i <= n; i++) {		printf("for %d top is %d tid is %d val is %d\n", 				i, top[i], tid[i], sval[tid[i]]);	}	printf("the maxv: ");	for(int i = 1; i <= n << 2; i++) printf("%d ", maxv[i]);	puts("");}int main() {	int T; scanf("%d", &T);	while(T--) {		init();		scanf("%d", &n);		for(int i = 1; i < n; i++) {			int a, b, c;			scanf("%d%d%d", &a, &b, &c);			adde(a, b, c, i); adde(b, a, c, i);		}		dfs1(1, 1, 1); dfs2(1, 1);		for(int i = 0; i < ecnt; i++) {			if(dep[u[i]] > dep[v[i]]) {				sval[tid[u[i]]] = w[i];				rnum[eid[i]] = tid[u[i]];			}			else {				sval[tid[v[i]]] = w[i];				rnum[eid[i]] = tid[v[i]];			}		}		build(1, 1, idcnt);		//debug();		char cmd[16];		int x, y;		while(scanf("%s", cmd)) {			if(strcmp(cmd, "DONE") == 0) break;			scanf("%d%d", &x, &y);			if(cmd[0] == ‘Q‘) {				printf("%d\n", ask(x, y));			}			else if(cmd[0] == ‘C‘) {				change(1, 1, idcnt, rnum[x], y);			}			else {				Negate(x, y);			}		}	}	return 0;}

  

POJ 3237 Tree 树链剖分