1 $.ajax({
 2    url: "http://query.yahooapis.com/v1/public/yql"
 3  , type:‘jsonp‘
 4  , data: {
 5    　　q: "select * from html where url=\"http://www.baidu.com/\"",
 6    　　format: "json"
 7    }
 8  , success:  (resp)=> {
 9    　　console.log(resp)
10    }
11 });