首页 > 代码库 > BZOJ 2049: [Sdoi2008]Cave 洞穴勘测
BZOJ 2049: [Sdoi2008]Cave 洞穴勘测
二次联通门 : BZOJ 2049: [Sdoi2008]Cave 洞穴勘测
其实指针也不是很慢
我的指针代码能吊打70%的数组
及80%的指针。。。。
/* BZOJ 2049: [Sdoi2008]Cave 洞穴勘测 LCT 连边 删边 查询是否在同一树中时, 只需要一直向上跳 看看树根是否相同就好了 */ #include <cstdio> #include <cstdlib> #include <iostream> #define Max 400009 int N; void read (int &now) { now = 0; register char word = getchar (); while (word < ‘0‘ || word > ‘9‘) word = getchar (); while (word >= ‘0‘ && word <= ‘9‘) { now = now * 10 + word - ‘0‘; word = getchar (); } } inline int min (int a, int b) { return a < b ? a : b; } struct Splay_Tree_Data { Splay_Tree_Data *child[2]; Splay_Tree_Data *father; int Flandre; Splay_Tree_Data () { Flandre = 0; father = NULL; child[0] = child[1] = NULL; } inline void Down () { if (!Flandre) return ; std :: swap (child[0], child[1]); Flandre = 0; if (child[0]) child[0]->Flandre ^= 1; if (child[1]) child[1]->Flandre ^= 1; } inline int Get_Pos () { return this->father->child[1] == this; } inline int Is_Root () { return !(this->father) || (this->father->child[0] != this && this->father->child[1] != this); } }; Splay_Tree_Data *data[Max]; Splay_Tree_Data *node[Max]; class Link_Cut_Tree_Type { private : inline void Rotate (Splay_Tree_Data *now) { int pos = now->Get_Pos () ^ 1; Splay_Tree_Data *Father = now->father; Father->child[pos ^ 1] = now->child[pos]; if (now->child[pos]) now->child[pos]->father = Father; now->father = Father->father; if (!(Father->Is_Root ())) now->father->child[Father->Get_Pos ()] = now; Father->father = now; now->child[pos] = Father; } inline void Splay (Splay_Tree_Data *now) { int Count = 0; for (Splay_Tree_Data *Father = now; ; Father = Father->father) { data[++Count] = Father; if (Father->Is_Root ()) break; } for (; Count >= 1; -- Count) data[Count]->Down (); for (; !(now->Is_Root ()); Rotate (now)) if (!(now->father->Is_Root ())) Rotate (now->Get_Pos () == now->father->Get_Pos () ? now->father : now); } inline void Access (Splay_Tree_Data *now) { for (Splay_Tree_Data *Father = NULL; now; Father = now, now = now->father) { Splay (now); now->child[1] = Father; } } inline void Make_Root (Splay_Tree_Data *now) { Access (now); Splay (now); now->Flandre ^= 1; } public : inline void Cut (Splay_Tree_Data *x, Splay_Tree_Data *y) { Make_Root (x); Access (y); Splay (y); x->father = y->child[0] = NULL; } inline void Link (Splay_Tree_Data *x, Splay_Tree_Data *y) { Make_Root (x); x->father = y; } int Query (Splay_Tree_Data *x, Splay_Tree_Data *y) { while (x->father) x = x->father; while (y->father) y = y->father; return x == y; } }; Link_Cut_Tree_Type Make; int main (int argc, char *argv[]) { read (N); char type[10]; int x, y; int M; for (int i = 0; i <= N; i ++) node[i] = new Splay_Tree_Data; for (read (M); M--; ) { scanf ("%s", type); read (x); read (y); if (type[0] == ‘Q‘) printf (Make.Query (node[x], node[y]) ? "Yes\n" : "No\n"); else if (type[0] == ‘C‘) Make.Link (node[x], node[y]); else Make.Cut (node[x], node[y]); } return 0; }
BZOJ 2049: [Sdoi2008]Cave 洞穴勘测
声明:以上内容来自用户投稿及互联网公开渠道收集整理发布,本网站不拥有所有权,未作人工编辑处理,也不承担相关法律责任,若内容有误或涉及侵权可进行投诉: 投诉/举报 工作人员会在5个工作日内联系你,一经查实,本站将立刻删除涉嫌侵权内容。