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Oracle统计某一年中的1-12个月的数据总和
查询2015年1月到12个月的所有实有人口数量和往年2014年1月到12个月的实有人口数量,没有的月份显示 人口数量为0.类似效果如图
创建表
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create table PERSONSITUATION ( id NUMBER not null , rdate DATE , nums NUMBER ) |
插入数据
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insert into PERSONSITUATION (id, rdate, nums) values (1, to_date( ‘26-01-2015‘ , ‘dd-mm-yyyy‘ ), 131); insert into PERSONSITUATION (id, rdate, nums) values (2, to_date( ‘27-01-2013‘ , ‘dd-mm-yyyy‘ ), 232); insert into PERSONSITUATION (id, rdate, nums) values (3, to_date( ‘18-10-2013‘ , ‘dd-mm-yyyy‘ ), 222); insert into PERSONSITUATION (id, rdate, nums) values (4, to_date( ‘20-01-2015‘ , ‘dd-mm-yyyy‘ ), 232); insert into PERSONSITUATION (id, rdate, nums) values (5, to_date( ‘28-01-2015‘ , ‘dd-mm-yyyy‘ ), 422); insert into PERSONSITUATION (id, rdate, nums) values (6, to_date( ‘26-02-2015‘ , ‘dd-mm-yyyy‘ ), 232); insert into PERSONSITUATION (id, rdate, nums) values (7, to_date( ‘29-01-2014‘ , ‘dd-mm-yyyy‘ ), 225); insert into PERSONSITUATION (id, rdate, nums) values (8, to_date( ‘31-01-2015‘ , ‘dd-mm-yyyy‘ ), 111); insert into PERSONSITUATION (id, rdate, nums) values (9, to_date( ‘25-01-2013‘ , ‘dd-mm-yyyy‘ ), 211); insert into PERSONSITUATION (id, rdate, nums) values (10, to_date( ‘25-01-2013‘ , ‘dd-mm-yyyy‘ ), 251); insert into PERSONSITUATION (id, rdate, nums) values (11, to_date( ‘25-01-2013‘ , ‘dd-mm-yyyy‘ ), 262); insert into PERSONSITUATION (id, rdate, nums) values (12, to_date( ‘25-08-2015‘ , ‘dd-mm-yyyy‘ ), 233); insert into PERSONSITUATION (id, rdate, nums) values (13, to_date( ‘25-01-2013‘ , ‘dd-mm-yyyy‘ ), 211); insert into PERSONSITUATION (id, rdate, nums) values (14, to_date( ‘25-02-2014‘ , ‘dd-mm-yyyy‘ ), 222); insert into PERSONSITUATION (id, rdate, nums) values (15, to_date( ‘25-03-2012‘ , ‘dd-mm-yyyy‘ ), 209); insert into PERSONSITUATION (id, rdate, nums) values (16, to_date( ‘25-01-2012‘ , ‘dd-mm-yyyy‘ ), 219); |
常见的统计中如下Sql语句,只查询到了数据中有的月,如果没有就什么也没有显示,和明显不符合1-12个月的12条数据统计
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select to_char(rdate, ‘yyyy-mm‘ ) rdate, sum (nums) nums from personsituation where to_char(rdate, ‘yyyy‘ )= ‘2015‘ group by to_char(rdate, ‘yyyy-mm‘ ) order by rdate |
正确的分析是:必须是12条数据,而且是统计的结果的12条数据,从这里入手编写如下Sql语句,显示12个列的统计数据,先查询出一年的数据,然后再连接另外一条数据拼接
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select sum (decode(to_char(rdate, ‘mm‘ ), ‘01‘ ,nums,0)) nums01, sum (decode(to_char(rdate, ‘mm‘ ), ‘02‘ ,nums,0)) nums02, sum (decode(to_char(rdate, ‘mm‘ ), ‘03‘ ,nums,0)) nums03, sum (decode(to_char(rdate, ‘mm‘ ), ‘04‘ ,nums,0)) nums04, sum (decode(to_char(rdate, ‘mm‘ ), ‘05‘ ,nums,0)) nums05, sum (decode(to_char(rdate, ‘mm‘ ), ‘06‘ ,nums,0)) nums06, sum (decode(to_char(rdate, ‘mm‘ ), ‘07‘ ,nums,0)) nums07, sum (decode(to_char(rdate, ‘mm‘ ), ‘08‘ ,nums,0)) nums08, sum (decode(to_char(rdate, ‘mm‘ ), ‘09‘ ,nums,0)) nums09, sum (decode(to_char(rdate, ‘mm‘ ), ‘10‘ ,nums,0)) nums10, sum (decode(to_char(rdate, ‘mm‘ ), ‘11‘ ,nums,0)) nums11, sum (decode(to_char(rdate, ‘mm‘ ), ‘12‘ ,nums,0)) nums12 from personsituation where to_char(rdate, ‘yyyy‘ )= ‘2015‘ |
而前端页面显示的结果有两种可能性,一种是横向展示,一种是纵向展示,可以使用下面的sql语句进行列转行的转换得到如下结果
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select * from ( select sum (decode(to_char(rdate, ‘mm‘ ), ‘01‘ ,nums,0)) nums01, sum (decode(to_char(rdate, ‘mm‘ ), ‘02‘ ,nums,0)) nums02, sum (decode(to_char(rdate, ‘mm‘ ), ‘03‘ ,nums,0)) nums03, sum (decode(to_char(rdate, ‘mm‘ ), ‘04‘ ,nums,0)) nums04, sum (decode(to_char(rdate, ‘mm‘ ), ‘05‘ ,nums,0)) nums05, sum (decode(to_char(rdate, ‘mm‘ ), ‘06‘ ,nums,0)) nums06, sum (decode(to_char(rdate, ‘mm‘ ), ‘07‘ ,nums,0)) nums07, sum (decode(to_char(rdate, ‘mm‘ ), ‘08‘ ,nums,0)) nums08, sum (decode(to_char(rdate, ‘mm‘ ), ‘09‘ ,nums,0)) nums09, sum (decode(to_char(rdate, ‘mm‘ ), ‘10‘ ,nums,0)) nums10, sum (decode(to_char(rdate, ‘mm‘ ), ‘11‘ ,nums,0)) nums11, sum (decode(to_char(rdate, ‘mm‘ ), ‘12‘ ,nums,0)) nums12 from personsituation where to_char(rdate, ‘yyyy‘ )= ‘2015‘ ) unpivot (sum2015 for years in (nums01,nums02,nums03,nums04,nums05,nums06,nums07,nums08,nums09,nums10,nums11,nums12) ) |
最后一步就是和往年的数据对比使用left join查询
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select A.years,A.SUM2015,B.SUM2014 from ( select * from ( select sum (decode(to_char(rdate, ‘mm‘ ), ‘01‘ ,nums,0)) nums01, sum (decode(to_char(rdate, ‘mm‘ ), ‘02‘ ,nums,0)) nums02, sum (decode(to_char(rdate, ‘mm‘ ), ‘03‘ ,nums,0)) nums03, sum (decode(to_char(rdate, ‘mm‘ ), ‘04‘ ,nums,0)) nums04, sum (decode(to_char(rdate, ‘mm‘ ), ‘05‘ ,nums,0)) nums05, sum (decode(to_char(rdate, ‘mm‘ ), ‘06‘ ,nums,0)) nums06, sum (decode(to_char(rdate, ‘mm‘ ), ‘07‘ ,nums,0)) nums07, sum (decode(to_char(rdate, ‘mm‘ ), ‘08‘ ,nums,0)) nums08, sum (decode(to_char(rdate, ‘mm‘ ), ‘09‘ ,nums,0)) nums09, sum (decode(to_char(rdate, ‘mm‘ ), ‘10‘ ,nums,0)) nums10, sum (decode(to_char(rdate, ‘mm‘ ), ‘11‘ ,nums,0)) nums11, sum (decode(to_char(rdate, ‘mm‘ ), ‘12‘ ,nums,0)) nums12 from personsituation where to_char(rdate, ‘yyyy‘ )= ‘2015‘ ) unpivot (sum2015 for years in (nums01,nums02,nums03,nums04,nums05,nums06,nums07,nums08,nums09,nums10,nums11,nums12) )) A left join ( select * from ( select sum (decode(to_char(rdate, ‘mm‘ ), ‘01‘ ,nums,0)) nums01, sum (decode(to_char(rdate, ‘mm‘ ), ‘02‘ ,nums,0)) nums02, sum (decode(to_char(rdate, ‘mm‘ ), ‘03‘ ,nums,0)) nums03, sum (decode(to_char(rdate, ‘mm‘ ), ‘04‘ ,nums,0)) nums04, sum (decode(to_char(rdate, ‘mm‘ ), ‘05‘ ,nums,0)) nums05, sum (decode(to_char(rdate, ‘mm‘ ), ‘06‘ ,nums,0)) nums06, sum (decode(to_char(rdate, ‘mm‘ ), ‘07‘ ,nums,0)) nums07, sum (decode(to_char(rdate, ‘mm‘ ), ‘08‘ ,nums,0)) nums08, sum (decode(to_char(rdate, ‘mm‘ ), ‘09‘ ,nums,0)) nums09, sum (decode(to_char(rdate, ‘mm‘ ), ‘10‘ ,nums,0)) nums10, sum (decode(to_char(rdate, ‘mm‘ ), ‘11‘ ,nums,0)) nums11, sum (decode(to_char(rdate, ‘mm‘ ), ‘12‘ ,nums,0)) nums12 from personsituation where to_char(rdate, ‘yyyy‘ )= ‘2014‘ ) unpivot (sum2014 for years in (nums01,nums02,nums03,nums04,nums05,nums06,nums07,nums08,nums09,nums10,nums11,nums12) )) B on A.years = B.years |
实现与效果图一样的数据,可以将sql中的nums01...nums12改为1月...12月
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select A.years,A.SUM1,B.SUM2 from ( select * from ( select sum (decode(to_char(rdate, ‘mm‘ ), ‘01‘ ,nums,0)) 一月, sum (decode(to_char(rdate, ‘mm‘ ), ‘02‘ ,nums,0)) 二月, sum (decode(to_char(rdate, ‘mm‘ ), ‘03‘ ,nums,0)) 三月, sum (decode(to_char(rdate, ‘mm‘ ), ‘04‘ ,nums,0)) 四月, sum (decode(to_char(rdate, ‘mm‘ ), ‘05‘ ,nums,0)) 五月, sum (decode(to_char(rdate, ‘mm‘ ), ‘06‘ ,nums,0)) 六月, sum (decode(to_char(rdate, ‘mm‘ ), ‘07‘ ,nums,0)) 七月, sum (decode(to_char(rdate, ‘mm‘ ), ‘08‘ ,nums,0)) 八月, sum (decode(to_char(rdate, ‘mm‘ ), ‘09‘ ,nums,0)) 九月, sum (decode(to_char(rdate, ‘mm‘ ), ‘10‘ ,nums,0)) 十月, sum (decode(to_char(rdate, ‘mm‘ ), ‘11‘ ,nums,0)) 十一月, sum (decode(to_char(rdate, ‘mm‘ ), ‘12‘ ,nums,0)) 十二月 from personsituation where to_char(rdate, ‘yyyy‘ )= ‘2015‘ ) unpivot (sum1 for years in (一月,二月,三月,四月,五月,六月,七月,八月, 九月,十月,十一月,十二月) )) A left join ( select * from ( select sum (decode(to_char(rdate, ‘mm‘ ), ‘01‘ ,nums,0)) 一月, sum (decode(to_char(rdate, ‘mm‘ ), ‘02‘ ,nums,0)) 二月, sum (decode(to_char(rdate, ‘mm‘ ), ‘03‘ ,nums,0)) 三月, sum (decode(to_char(rdate, ‘mm‘ ), ‘04‘ ,nums,0)) 四月, sum (decode(to_char(rdate, ‘mm‘ ), ‘05‘ ,nums,0)) 五月, sum (decode(to_char(rdate, ‘mm‘ ), ‘06‘ ,nums,0)) 六月, sum (decode(to_char(rdate, ‘mm‘ ), ‘07‘ ,nums,0)) 七月, sum (decode(to_char(rdate, ‘mm‘ ), ‘08‘ ,nums,0)) 八月, sum (decode(to_char(rdate, ‘mm‘ ), ‘09‘ ,nums,0)) 九月, sum (decode(to_char(rdate, ‘mm‘ ), ‘10‘ ,nums,0)) 十月, sum (decode(to_char(rdate, ‘mm‘ ), ‘11‘ ,nums,0)) 十一月, sum (decode(to_char(rdate, ‘mm‘ ), ‘12‘ ,nums,0)) 十二月 from personsituation where to_char(rdate, ‘yyyy‘ )= ‘2014‘ ) unpivot (sum2 for years in (一月,二月,三月,四月,五月,六月,七月,八月, 九月,十月,十一月,十二月) )) B on A.years = B.years |
Oracle统计某一年中的1-12个月的数据总和
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