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Leetcode Intersection of Two Linked Lists
/** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; */class Solution {public: ListNode *getIntersectionNode(ListNode *headA, ListNode *headB) { int lena = count(headA); int lenb = count(headB); int diff = 0; ListNode* longer = NULL; ListNode* shorter= NULL; if (lena > lenb) { diff = lena - lenb; longer = headA; shorter= headB; } else { diff = lenb - lena; longer = headB; shorter= headA; } longer = forward(longer, diff); while (longer != shorter) { longer = forward(longer, 1); shorter= forward(shorter, 1); } return longer; } ListNode* forward(ListNode* head, int step) { while(head != NULL) { if (step-- <= 0) { break; } head = head->next; } return head; } int count(ListNode* head) { int res = 0; while (head != NULL) { head = head->next; res++; } return res; }};
Leetcode 也有可视化了,越来越高端了
Leetcode Intersection of Two Linked Lists
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