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Unsorted, maximum ==> sorted
https://github.com/Premiumlab/Python-for-Algorithms--Data-Structures--and-Interviews/blob/master/Mock%20Interviews/Social%20Network%20Company/Social%20Network%20Company%20-%20Interview%20Questions%20-%20SOLUTIONS/On-Site%20Question%203%20-%20SOLUTION.ipynb
On-Site Question 3 - SOLUTION
Problem
Create a function that takes in a list of unsorted prices (integers) and a maximum possible price value, and return a sorted list of prices
Requirements
Your function should be able to perform this in less than O(nlogn) time.
Solution
We can actually solve this problem by using a counting sort. Basically a counting sort works well when you know the range of integer values you will have ahead of time.
Read the wikipedia article linked above for a full break down, and an implementation is here below (using the prices situation described in the problem above).
def solution(unsorted_prices,max_price): # list of 0s at indices 0 to max_price prices_to_counts = [0]* (max_price+1) # populate prices for price in unsorted_prices: prices_to_counts[price] +=1 # populate final sorted prices sorted_prices = [] # For each price in prices_to_counts for price,count in enumerate(prices_to_counts): # for the number of times the element occurs for time in range(count): # add it to the sorted price list sorted_prices.append(price) return sorted_prices
solution([4,6,2,7,3,8,9],9)
[2, 3, 4, 6, 7, 8, 9]
This was a great exercise in learning about a new sorting algorithm, make sure to read up on it and practice this problem again!
Good Job!
Unsorted, maximum ==> sorted