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python:BeautifulSoup学习

上一篇说到用BeautifulSoup解析源代码,下面我们就来实战一下:

 1 from bs4 import BeautifulSoup
 2 html = urllib.request.urlopen(http://www.massey.ac.nz/massey/learning/programme-course/programme.cfm?prog_id=93536)
 3 html = html.read().decode(utf-8)
 4 soup = BeautifulSoup(html)
 5 """
 6 or you can do:
 7     soup = BeautifulSoup(open(‘F:\\forpython\\Master of Counselling Studies (MCounsStuds) - 2017 - Massey University.html‘,encoding = ‘utf-8‘))
 8 """
 9 soup.find_all(h1)
10 soup.h1.get_text()

其实用open的方式可以避免decode报错,可以的话还是用open比较好。运行结果:

1 soup.find_all(h1)
2 Out[76]: [<h1>Master of Advanced Leadership Practice (<span>MALP</span>)</h1>]

噌~是不是快了许多,还有更快的:

1 soup.h1.get_text()
2 Out[75]: Master of Advanced Leadership Practice (MALP)

h1其实是一个标签,用BeautifulSoup解析过后可以直接引用,下面我们直接引用title标签(学过html的同学会知道title标签)

1 soup.title
2 Out[79]: <title>Master of Advanced Leadership Practice (MALP) - 2017 - Massey University</title>

接下来我们用BeautifulSoup帮助我们爬一张图片:技术分享

右键单击,选择‘检查’(我用的Google浏览器)

技术分享

通过右边的elements一步一步的查找图片所在的源代码(你把鼠标放在源代码上会显现相应的位置)

技术分享

 

 看到了吧,在<div,class="block block-feature-image">下,我们使用BeautifulSoup开始撸:

1 a = soup.find(div,{class:"block block-feature-image"}).figure.img.attrs[src]
2 # soup.figure.img.attrs[‘src‘] 这样也可以
3 a
4 Out[129]: /massey/fms/Study/StudyAtMassey/Images/prog_images/93059.jpg

attrs是属性的意思,img.attrs[‘src‘]就是调出img对象src的属性值(这个语法我也不是很懂,好像是xpath的语法)。再把网址的头添加上去,写入本地文件:

1 a1 = http://www.massey.ac.nz+a
2 pic = urllib.request.urlopen(a1).read()
3 pic_data=http://www.mamicode.com/open(F:/1.jpg,wb)
4 pic_data.write(pic)
5 pic_data.close()

技术分享

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python:BeautifulSoup学习