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nyoj 714 Card Trick
Card Trick
时间限制:1000 ms | 内存限制:65535 KB
难度:3
描述
The magician shuffles a small pack of cards, holds it face down and performs the following procedure:
- The top card is moved to the bottom of the pack. The new top card is dealt face up onto the table. It is the Ace of Spades.
- Two cards are moved one at a time from the top to the bottom. The next card is dealt face up onto the table. It is the Two of Spades.
- Three cards are moved one at a time…
- This goes on until the nth and last card turns out to be the n of Spades.
This impressive trick works if the magician knows how to arrange the cards beforehand (and knows how to give a false shuffle). Your program has to determine the initial order of the cards for a given number of cards, 1 ≤ n ≤ 13.
输入
On the first line of the input is a single positive integer k, telling the number of test cases to follow. 1 ≤ k ≤ 10 Each case consists of one line containing the integer n. 1 ≤ n ≤ 13
输出
For each test case, output a line with the correct permutation of the values 1 to n, space separated. The first number showing the top card of the pack, etc…
样例输入
2
4
5
样例输出
2 1 4 3
3 1 4 5 2
#include<cstdio> #include<cstring> int a[15][15]={{1},{2,1},{3,1,2},{2,1,4,3},{3,1,4,5,2},{4,1,6,3,2,5},{5,1,3,4,2,6,7},{3,1,7,5,2,6,8,4},{7,1,8,6,2,9,4,5,3}, {9,1,8,5,2,4,7,6,3,10},{5,1,6,4,2,10,11,7,3,8,9},{7,1,4,9,2,11,10,8,3,6,5,12},{4,1,13,11,2,10,6,7,3,5,12,9,8}}; int main() { int t,n; scanf("%d",&t); while(t--) { scanf("%d",&n); for(int i=0;i<n;i++) printf("%d ",a[n-1][i]); printf("\n"); } return 0; }
nyoj 714 Card Trick