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Leetcode-Search Insert Position
Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order.
You may assume no duplicates in the array.
Here are few examples.[1,3,5,6], 5 → 2[1,3,5,6], 2 → 1[1,3,5,6], 7 → 4[1,3,5,6], 0 → 0
Have you met this question in a real interview?
Analysis:
It is a binary search problem. Just need to consider the corner cases carefully!
Solution:
1 public class Solution { 2 public int searchInsert(int[] A, int target) { 3 int len = A.length; 4 if (len==0) return -1; 5 6 int head = 0, end = A.length-1; 7 8 //NOTE:Consider these coner cases carefully! 9 if (target<=A[head]) return head;10 if (target>A[end]) return end+1;11 else if (target==A[end]) return end;12 13 while (end-head>1){14 int mid = (head+end)/2;15 if (A[mid]==target) return mid;16 else if (A[mid]>target)17 end = mid;18 else19 head = mid;20 }21 return end;22 23 }24 }
Leetcode-Search Insert Position
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