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Leetcode-Remove Duplicates from Sorted List II
Given a sorted linked list, delete all nodes that have duplicate numbers, leaving only distinct numbers from the original list.
For example,
Given 1->2->3->3->4->4->5
, return 1->2->5
.
Given 1->1->1->2->3
, return 2->3
.
Solution:
1 /** 2 * Definition for singly-linked list. 3 * public class ListNode { 4 * int val; 5 * ListNode next; 6 * ListNode(int x) { 7 * val = x; 8 * next = null; 9 * }10 * }11 */12 public class Solution {13 public ListNode deleteDuplicates(ListNode head) {14 if (head==null || head.next==null) return head;15 ListNode preHead = new ListNode(-1);16 preHead.next = head;17 ListNode cur = head;18 ListNode pre = preHead;19 20 //NOTE:We need to be every carefull about the condition,21 //because if the last node be deleted, the cur is null in the next step.22 //however, if the node before the last node is deleted, the cur is the last node in the next step,23 //we then need to stop also, otherwise cur.next.val is invalid.24 while (cur!=null && cur.next!=null){25 if (cur.val==cur.next.val){26 while (cur.val==cur.next.val){27 cur.next = cur.next.next;28 if (cur.next==null)29 break;30 }31 pre.next = cur.next; 32 cur = pre.next;33 } else {34 pre = cur;35 cur = cur.next;36 if (cur.next==null)37 break;38 }39 }40 41 return preHead.next; 42 }43 }
Leetcode-Remove Duplicates from Sorted List II
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