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很强大的shell写的俄罗斯方块
网上看到的一个用linux的shell脚本写的俄罗斯方块。
是我至今见过写的最牛逼的shell了。共享一下。
原作者信息在脚本的凝视中有。
下载地址：点击下载
#!/bin/bash
# Tetris Game
# 10.21.2003 xhchen<[email]xhchen@winbond.com.tw[/email]>
#APP declaration
APP_NAME="${0##*[\\/]}"
APP_VERSION="1.0"
#颜色定义
cRed=1
cGreen=2
cYellow=3
cBlue=4
cFuchsia=5
cCyan=6
cWhite=7
colorTable=($cRed $cGreen $cYellow $cBlue $cFuchsia $cCyan $cWhite)
#位置和大小
iLeft=3
iTop=2
((iTrayLeft = iLeft + 2))
((iTrayTop = iTop + 1))
((iTrayWidth = 10))
((iTrayHeight = 15))
#颜色设置
cBorder=$cGreen
cScore=$cFuchsia
cScoreValue=http://www.mamicode.com/$cCyan"\033"`
cSpace=`echo -ne "\040"`
#保存终端属性。在read -s读取终端键时，终端的属性会被临时改变。
#假设在read -s时程序被不幸杀掉，可能会导致终端混乱，
#须要在程序退出时恢复终端属性。
sTTY=`stty -g`
#捕捉退出信号
trap "MyExit;" INT TERM
trap "MyExitNoSub;" $sigExit
#隐藏光标
echo -ne "\033[?25l"
while :
do
#读取输入。注-s不回显。-n读到一个字符马上返回
read -s -n 1 key
aKey[0]=${aKey[1]}
aKey[1]=${aKey[2]}
aKey[2]=$key
sig=0
#推断输入了何种键
if [[ $key == $cESC && ${aKey[1]} == $cESC ]]
then
#ESC键
MyExit
elif [[ ${aKey[0]} == $cESC && ${aKey[1]} == "[" ]]
then
if [[ $key == "A" ]]; then sig=$sigRotate #<向上键>
elif [[ $key == "B" ]]; then sig=$sigDown #<向下键>
elif [[ $key == "D" ]]; then sig=$sigLeft #<向左键>
elif [[ $key == "C" ]]; then sig=$sigRight #<向右键>
fi
elif [[ $key == "W" || $key == "w" ]]; then sig=$sigRotate #W, w
elif [[ $key == "S" || $key == "s" ]]; then sig=$sigDown #S, s
elif [[ $key == "A" || $key == "a" ]]; then sig=$sigLeft #A, a
elif [[ $key == "D" || $key == "d" ]]; then sig=$sigRight #D, d
elif [[ "[$key]" == "[]" ]]; then sig=$sigAllDown #空格键
elif [[ $key == "Q" || $key == "q" ]] #Q, q
then
MyExit
fi
if [[ $sig != 0 ]]
then
#向还有一进程发送消息
kill -$sig $pidDisplayer
fi
done
}
#退出前的恢复
function MyExitNoSub()
{
local y
#恢复终端属性
stty $sTTY
((y = iTop + iTrayHeight + 4))
#显示光标
echo -e "\033[?25h\033[${y};0H"
exit
}
function MyExit()
{
#通知显示进程须要退出
kill -$sigExit $pidDisplayer
MyExitNoSub
}
#处理显示和游戏流程的主函数
function RunAsDisplayer()
{
local sigThis
InitDraw
#挂载各种信号的处理函数
trap "sig=$sigRotate;" $sigRotate
trap "sig=$sigLeft;" $sigLeft
trap "sig=$sigRight;" $sigRight
trap "sig=$sigDown;" $sigDown
trap "sig=$sigAllDown;" $sigAllDown
trap "ShowExit;" $sigExit
while :
do
#依据当前的速度级iLevel不同，设定对应的循环的次数
for ((i = 0; i < 21 - iLevel; i++))
do
sleep 0.02
sigThis=$sig
sig=0
#依据sig变量推断是否接受到对应的信号
if ((sigThis == sigRotate)); then BoxRotate; #旋转
elif ((sigThis == sigLeft)); then BoxLeft; #左移一列
elif ((sigThis == sigRight)); then BoxRight; #右移一列
elif ((sigThis == sigDown)); then BoxDown; #下落一行
elif ((sigThis == sigAllDown)); then BoxAllDown; #下落究竟
fi
done
#kill -$sigDown $$
BoxDown #下落一行
done
}
#BoxMove(y, x), 測试能否够把移动中的方块移到(x, y)的位置, 返回0则能够, 1不能够
function BoxMove()
{
local j i x y xTest yTest
yTest=$1
xTest=$2
for ((j = 0; j < 8; j += 2))
do
((i = j + 1))
((y = ${boxCur[$j]} + yTest))
((x = ${boxCur[$i]} + xTest))
if (( y < 0 || y >= iTrayHeight || x < 0 || x >= iTrayWidth))
then
#撞到墙壁了
return 1
fi
if ((${iMap[y * iTrayWidth + x]} != -1 ))
then
#撞到其它已经存在的方块了
return 1
fi
done
return 0;
}
#将当前移动中的方块放到背景方块中去,
#并计算新的分数和速度级。(即一次方块落究竟部)
function Box2Map()
{
local j i x y xp yp line
#将当前移动中的方块放到背景方块中去
for ((j = 0; j < 8; j += 2))
do
((i = j + 1))
((y = ${boxCur[$j]} + boxCurY))
((x = ${boxCur[$i]} + boxCurX))
((i = y * iTrayWidth + x))
iMap[$i]=$cBoxCur
done
#消去可被消去的行
line=0
for ((j = 0; j < iTrayWidth * iTrayHeight; j += iTrayWidth))
do
for ((i = j + iTrayWidth - 1; i >= j; i--))
do
if ((${iMap[$i]} == -1)); then break; fi
done
if ((i >= j)); then continue; fi
((line++))
for ((i = j - 1; i >= 0; i--))
do
((x = i + iTrayWidth))
iMap[$x]=${iMap[$i]}
done
for ((i = 0; i < iTrayWidth; i++))
do
iMap[$i]=-1
done
done
if ((line == 0)); then return; fi
#依据消去的行数line计算分数和速度级
((x = iLeft + iTrayWidth * 2 + 7))
((y = iTop + 11))
((iScore += line * 2 - 1))
#显示新的分数
echo -ne "\033[1m\033[3${cScoreValue}m\033[${y};${x}H${iScore} "
if ((iScore % iScoreEachLevel < line * 2 - 1))
then
if ((iLevel < 20))
then
((iLevel++))
((y = iTop + 14))
#显示新的速度级
echo -ne "\033[3${cScoreValue}m\033[${y};${x}H${iLevel} "
fi
fi
echo -ne "\033[0m"
#又一次显示背景方块
for ((y = 0; y < iTrayHeight; y++))
do
((yp = y + iTrayTop + 1))
((xp = iTrayLeft + 1))
((i = y * iTrayWidth))
echo -ne "\033[${yp};${xp}H"
for ((x = 0; x < iTrayWidth; x++))
do
((j = i + x))
if ((${iMap[$j]} == -1))
then
echo -ne " "
else
echo -ne "\033[1m\033[7m\033[3${iMap[$j]}m\033[4${iMap[$j]}m[]\033[0m"
fi
done
done
}
#下落一行
function BoxDown()
{
local y s
((y = boxCurY + 1)) #新的y坐标
if BoxMove $y $boxCurX #測试能否够下落一行
then
s="`DrawCurBox 0`" #将旧的方块抹去
((boxCurY = y))
s="$s`DrawCurBox 1`" #显示新的下落后方块
echo -ne $s
else
#走到这儿, 假设不能下落了
Box2Map #将当前移动中的方块贴到背景方块中
RandomBox #产生新的方块
fi
}
#左移一列
function BoxLeft()
{
local x s
((x = boxCurX - 1))
if BoxMove $boxCurY $x
then
s=`DrawCurBox 0`
((boxCurX = x))
s=$s`DrawCurBox 1`
echo -ne $s
fi
}
#右移一列
function BoxRight()
{
local x s
((x = boxCurX + 1))
if BoxMove $boxCurY $x
then
s=`DrawCurBox 0`
((boxCurX = x))
s=$s`DrawCurBox 1`
echo -ne $s
fi
}
#下落究竟
function BoxAllDown()
{
local k j i x y iDown s
iDown=$iTrayHeight
#计算一共须要下落多少行
for ((j = 0; j < 8; j += 2))
do
((i = j + 1))
((y = ${boxCur[$j]} + boxCurY))
((x = ${boxCur[$i]} + boxCurX))
for ((k = y + 1; k < iTrayHeight; k++))
do
((i = k * iTrayWidth + x))
if (( ${iMap[$i]} != -1)); then break; fi
done
((k -= y + 1))
if (( $iDown > $k )); then iDown=$k; fi
done
s=`DrawCurBox 0` #将旧的方块抹去
((boxCurY += iDown))
s=$s`DrawCurBox 1` #显示新的下落后的方块
echo -ne $s
Box2Map #将当前移动中的方块贴到背景方块中
RandomBox #产生新的方块
}
#旋转方块
function BoxRotate()
{
local iCount iTestRotate boxTest j i s
iCount=${countBox[$iBoxCurType]} #当前的方块经旋转能够产生的样式的数目
#计算旋转后的新的样式
((iTestRotate = iBoxCurRotate + 1))
if ((iTestRotate >= iCount))
then
((iTestRotate = 0))
fi
#更新到新的样式, 保存老的样式(但不显示)
for ((j = 0, i = (${offsetBox[$iBoxCurType]} + $iTestRotate) * 8; j < 8; j++, i++))
do
boxTest[$j]=${boxCur[$j]}
boxCur[$j]=${box[$i]}
done
if BoxMove $boxCurY $boxCurX #測试旋转后是否有空间放的下
then
#抹去旧的方块
for ((j = 0; j < 8; j++))
do
boxCur[$j]=${boxTest[$j]}
done
s=`DrawCurBox 0`
#画上新的方块
for ((j = 0, i = (${offsetBox[$iBoxCurType]} + $iTestRotate) * 8; j < 8; j++, i++))
do
boxCur[$j]=${box[$i]}
done
s=$s`DrawCurBox 1`
echo -ne $s
iBoxCurRotate=$iTestRotate
else
#不能旋转，还是继续使用老的样式
for ((j = 0; j < 8; j++))
do
boxCur[$j]=${boxTest[$j]}
done
fi
}
#DrawCurBox(bDraw), 绘制当前移动中的方块, bDraw为1, 画上, bDraw为0, 抹去方块。
function DrawCurBox()
{
local i j t bDraw sBox s
bDraw=$1
s=""
if (( bDraw == 0 ))
then
sBox="\040\040"
else
sBox="[]"
s=$s"\033[1m\033[7m\033[3${cBoxCur}m\033[4${cBoxCur}m"
fi
for ((j = 0; j < 8; j += 2))
do
((i = iTrayTop + 1 + ${boxCur[$j]} + boxCurY))
((t = iTrayLeft + 1 + 2 * (boxCurX + ${boxCur[$j + 1]})))
#\033[y;xH, 光标到(x, y)处
s=$s"\033[${i};${t}H${sBox}"
done
s=$s"\033[0m"
echo -n $s
}
#更新新的方块
function RandomBox()
{
local i j t
#更新当前移动的方块
iBoxCurType=${iBoxNewType}
iBoxCurRotate=${iBoxNewRotate}
cBoxCur=${cBoxNew}
for ((j = 0; j < ${#boxNew[@]}; j++))
do
boxCur[$j]=${boxNew[$j]}
done
#显示当前移动的方块
if (( ${#boxCur[@]} == 8 ))
then
#计算当前方块该从顶端哪一行"冒"出来
for ((j = 0, t = 4; j < 8; j += 2))
do
if ((${boxCur[$j]} < t)); then t=${boxCur[$j]}; fi
done
((boxCurY = -t))
for ((j = 1, i = -4, t = 20; j < 8; j += 2))
do
if ((${boxCur[$j]} > i)); then i=${boxCur[$j]}; fi
if ((${boxCur[$j]} < t)); then t=${boxCur[$j]}; fi
done
((boxCurX = (iTrayWidth - 1 - i - t) / 2))
#显示当前移动的方块
echo -ne `DrawCurBox 1`
#假设方块一出来就没处放，Game over!
if ! BoxMove $boxCurY $boxCurX
then
kill -$sigExit ${PPID}
ShowExit
fi
fi
#清除右边预显示的方块
for ((j = 0; j < 4; j++))
do
((i = iTop + 1 + j))
((t = iLeft + 2 * iTrayWidth + 7))
echo -ne "\033[${i};${t}H "
done
#随机产生新的方块
((iBoxNewType = RANDOM % ${#offsetBox[@]}))
((iBoxNewRotate = RANDOM % ${countBox[$iBoxNewType]}))
for ((j = 0, i = (${offsetBox[$iBoxNewType]} + $iBoxNewRotate) * 8; j < 8; j++, i++))
do
boxNew[$j]=${box[$i]};
done
((cBoxNew = ${colorTable[RANDOM % ${#colorTable[@]}]}))
#显示右边预显示的方块
echo -ne "\033[1m\033[7m\033[3${cBoxNew}m\033[4${cBoxNew}m"
for ((j = 0; j < 8; j += 2))
do
((i = iTop + 1 + ${boxNew[$j]}))
((t = iLeft + 2 * iTrayWidth + 7 + 2 * ${boxNew[$j + 1]}))
echo -ne "\033[${i};${t}H[]"
done
echo -ne "\033[0m"
}
#初始绘制
function InitDraw()
{
clear
RandomBox #随机产生方块。这时右边预显示窗体中有方快了
RandomBox #再随机产生方块。右边预显示窗体中的方块被更新，原先的方块将開始下落
local i t1 t2 t3
#显示边框
echo -ne "\033[1m"
echo -ne "\033[3${cBorder}m\033[4${cBorder}m"
((t2 = iLeft + 1))
((t3 = iLeft + iTrayWidth * 2 + 3))
for ((i = 0; i < iTrayHeight; i++))
do
((t1 = i + iTop + 2))
echo -ne "\033[${t1};${t2}H||"
echo -ne "\033[${t1};${t3}H||"
done
((t2 = iTop + iTrayHeight + 2))
for ((i = 0; i < iTrayWidth + 2; i++))
do
((t1 = i * 2 + iLeft + 1))
echo -ne "\033[${iTrayTop};${t1}H=="
echo -ne "\033[${t2};${t1}H=="
done
echo -ne "\033[0m"
#显示"Score"和"Level"字样
echo -ne "\033[1m"
((t1 = iLeft + iTrayWidth * 2 + 7))
((t2 = iTop + 10))
echo -ne "\033[3${cScore}m\033[${t2};${t1}HScore"
((t2 = iTop + 11))
echo -ne "\033[3${cScoreValue}m\033[${t2};${t1}H${iScore}"
((t2 = iTop + 13))
echo -ne "\033[3${cScore}m\033[${t2};${t1}HLevel"
((t2 = iTop + 14))
echo -ne "\033[3${cScoreValue}m\033[${t2};${t1}H${iLevel}"
echo -ne "\033[0m"
}
#退出时显示GameOVer!
function ShowExit()
{
local y
((y = iTrayHeight + iTrayTop + 3))
echo -e "\033[${y};0HGameOver!\033[0m"
exit
}
#显示使用方法.
function Usage
{
cat << EOF
Usage: $APP_NAME
Start tetris game.
-h, --help display this help and exit
--version output version information and exit
EOF
}
#游戏主程序在这儿開始.
if [[ "$1" == "-h" || "$1" == "--help" ]]; then
Usage
elif [[ "$1" == "--version" ]]; then
echo "$APP_NAME $APP_VERSION"
elif [[ "$1" == "--show" ]]; then
#当发现具有參数--show时，执行显示函数
RunAsDisplayer
else
bash $0 --show& #以參数--show将本程序再执行一遍
RunAsKeyReceiver $! #以上一行产生的进程的进程号作为參数
fi
很强大的shell写的俄罗斯方块