http://acm.hdu.edu.cn/showproblem.php?pid=4296

找sum-w[i]-s[i]的最小值即可了。O(n)

//#pragma comment(linker, "/STACK:102400000,102400000")
#include <cstdio>
#include <cstring>
#include <algorithm>
#include <string>
#include <iostream>
#include <iomanip>
#include <cmath>
#include <map>
#include <set>
#include <queue>
using namespace std;

#define ls(rt) rt*2
#define rs(rt) rt*2+1
#define ll long long
#define ull unsigned long long
#define rep(i,s,e) for(int i=s;i<e;i++)
#define repe(i,s,e) for(int i=s;i<=e;i++)
#define CL(a,b) memset(a,b,sizeof(a))
#define IN(s) freopen(s,"r",stdin)
#define OUT(s) freopen(s,"w",stdout)
const ll ll_INF = ((ull)(-1))>>1;
const double EPS = 1e-8;
const double pi = acos(-1.0);
const int INF = 100000000;

const int MAXN = 100000+20;
int w[MAXN],s[MAXN];

int main()
{
    int n,pos;
    ll sum,mmin;
    while(~scanf("%d",&n))
    {
        sum=0;
        for(int i=0;i<n;i++)
            scanf("%d%d",&w[i],&s[i]),sum+=w[i];
        mmin=sum-w[0]-s[0];
        pos=0;
        for(int i=1;i<n;i++)
            if(mmin>sum-w[i]-s[i])pos=i,mmin=sum-w[i]-s[i];
        printf("%I64d\n",mmin);
    }
    return 0;
}