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JDK之ConcurrentHashMap分析
对ConcurrentHashMap是一个线程安全的map感到好奇,所以就试着去看了看JDK的源码
ConcurrentHashMap分成一个一个的段。然后每次要put或get元素的时候,就先找到这个段,然后执行put或get。为了线程安全,在put方法里面加了锁
看下segment这个属性
final Segment<K,V>[] segments;Segmen里面有下面这个属性
transient volatile HashEntry<K,V>[] table;在看下HashEntry
static final class HashEntry<K,V> { final K key; final int hash; volatile V value; final HashEntry<K,V> next; HashEntry(K key, int hash, HashEntry<K,V> next, V value) { this.key = key; this.hash = hash; this.next = next; this.value = http://www.mamicode.com/value;>
这不就是用来存键值对的么。。。
再来看看ConcurrentHashMap的put方法
public V put(K key, V value) { if (value =http://www.mamicode.com/= null)>就是通过segmentFor方法找到那个segment,然后交给那个segment去进行put操作
在看看Segment类中的put方法
V put(K key, int hash, V value, boolean onlyIfAbsent) { lock(); try { int c = count; if (c++ > threshold) // ensure capacity rehash(); HashEntry<K,V>[] tab = table; int index = hash & (tab.length - 1); HashEntry<K,V> first = tab[index]; HashEntry<K,V> e = first; while (e != null && (e.hash != hash || !key.equals(e.key))) e = e.next; V oldValue; if (e != null) { oldValue = http://www.mamicode.com/e.value;>就是先加了个锁,然后通过hash值找到对象的数组下标。然后循环这些hash值相同的e节点,如果key相同就替代它的value值,否则就进行插入的动作。然后手动释放锁。这个保证了线程的安全,有比hashtable的效率高多了。因为hashtable对它的方法都进行了同步。
ConcurrentHashMap里面有个size方法,也值得看一下。
public int size() { final Segment<K,V>[] segments = this.segments; long sum = 0; long check = 0; int[] mc = new int[segments.length]; // Try a few times to get accurate count. On failure due to // continuous async changes in table, resort to locking. for (int k = 0; k < RETRIES_BEFORE_LOCK; ++k) { check = 0; sum = 0; int mcsum = 0; for (int i = 0; i < segments.length; ++i) { sum += segments[i].count; mcsum += mc[i] = segments[i].modCount; } if (mcsum != 0) { for (int i = 0; i < segments.length; ++i) { check += segments[i].count; if (mc[i] != segments[i].modCount) { check = -1; // force retry break; } } } if (check == sum) break; } if (check != sum) { // Resort to locking all segments sum = 0; for (int i = 0; i < segments.length; ++i) segments[i].lock(); for (int i = 0; i < segments.length; ++i) sum += segments[i].count; for (int i = 0; i < segments.length; ++i) segments[i].unlock(); } if (sum > Integer.MAX_VALUE) return Integer.MAX_VALUE; else return (int)sum; }
JDK之ConcurrentHashMap分析
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