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Jump Game
Dynamic Programming
参考：http://fisherlei.blogspot.com/2012/12/leetcode-jump-game.html
http://blog.csdn.net/linhuanmars/article/details/21354751
Given an array of non-negative integers, you are initially positioned at the first index of the array.
Each element in the array represents your maximum jump length at that position.
Determine if you are able to reach the last index.
For example:
A = [2,3,1,1,4], return true.
A = [3,2,1,0,4], return false.
C++实现代码：
#include<iostream>using namespace std;class Solution{public: bool canJump(int A[],int n) { int maxSum=0; int sum=0; int i; for(i=0;i<=maxSum&&i<n;i++) { sum=i+A[i]; if(sum>maxSum) maxSum=sum; if(maxSum>=n-1) return true; } return false; }};int main(){ Solution s; int A[5]={3,2,1,0,4}; cout<<s.canJump(A,5)<<endl;}
Jump Game
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