读入两个小于10000的正整数A和B,计算A+B.
需要注意的是:A和B的每一位数字由对应的英文单词给出.

测试输入包含若干测试用例,每个测试用例占一行,格式为"A + B =",相邻两字符串有一个空格间隔.当A和B同时为0时输入结束,相应的结果不要输出.

对每个测试用例输出1行,即A+B的值.

#include<stdio.h>#include<string.h>int main(){	int i,j;	int x,y,m,n,t; 	char a[1000],b[1000],c[100][100],d[100][100],str[10000];	while(gets(str))	{ 		t=0;		for(i=0;str[i];i++)		{			if(str[i]=='+')			{				a[t-1]='\0';//因为“+”前有一个空格				break;			}			else				a[t++]=str[i];		}		a[t]='\0';		t=0;		for(j=i+2;str[j];j++)//（j=i+2）因为“+”后有一个空格		{			if(str[j]=='=')			{				b[t-1]='\0';//因为“=”前有一个空格				break;			}			else				b[t++]=str[j];		}		b[t]='\0';				if(strcmp(a,"zero")==0&&strcmp(b,"zero")==0)			break;		//printf("%s\n",a);	//	printf("%s\n",b);		m=0;		n=0;		for(i=0;a[i];i++)		{			if(a[i]==' ')			{				d[m][n++]='\0';				m++;				n=0;			}			else				d[m][n++]=a[i];		}		d[m++][n]='\0';		x=0;		for(i=0;i<m;i++)		{			if(strcmp(d[i],"one")==0)			{				j=1;				x=x*10+j;			}			else if(strcmp(d[i],"two")==0)			{				j=2;				x=x*10+j;			}			else if(strcmp(d[i],"three")==0)			{				j=3;				x=x*10+j;			}			else if(strcmp(d[i],"four")==0)			{				j=4;				x=x*10+j;			}			else if(strcmp(d[i],"five")==0)			{				j=5;				x=x*10+j;			}			else if(strcmp(d[i],"six")==0)			{				j=6;				x=x*10+j;			}			else if(strcmp(d[i],"seven")==0)			{				j=7;				x=x*10+j;			}			else if(strcmp(d[i],"eight")==0)			{				j=8;				x=x*10+j;			}			else if(strcmp(d[i],"nine")==0)			{				j=9;				x=x*10+j;			}			else if(strcmp(d[i],"zero")==0)			{				j=0;				x=x*10+j;			}		}		m=0;		n=0;				for(i=0;b[i];i++)		{			if(b[i]==' ')			{				c[m][n++]='\0';				m++;				n=0;			}			else				c[m][n++]=b[i];		}		c[m++][n]='\0';		y=0;		for(i=0;i<m;i++)		{			if(strcmp(c[i],"one")==0)			{				j=1;				y=y*10+j;			}			else if(strcmp(c[i],"two")==0)			{				j=2;				y=y*10+j;			}			else if(strcmp(c[i],"three")==0)			{				j=3;				y=y*10+j;			}			else if(strcmp(c[i],"four")==0)			{				j=4;				y=y*10+j;			}			else if(strcmp(c[i],"five")==0)			{				j=5;				y=y*10+j;			}			else if(strcmp(c[i],"six")==0)			{				j=6;				y=y*10+j;			}			else if(strcmp(c[i],"seven")==0)			{				j=7;				y=y*10+j;			}			else if(strcmp(c[i],"eight")==0)			{				j=8;				y=y*10+j;			}			else if(strcmp(c[i],"nine")==0)			{				j=9;				y=y*10+j;			}			else if(strcmp(c[i],"zero")==0)			{				j=0;				y=y*10+j;			}		}		printf("%d\n",x+y);	}	return 0;}

#include <iostream>#include <string>#include <string.h>#include <stdio.h>using namespace std; int digital(string str)  {    if(str == "one")        return 1 ;    else if(str == "two")        return 2 ;    else if(str == "three")        return 3 ;    else if(str == "four")        return 4 ;    else if(str == "five")        return 5 ;    else if(str == "six")        return 6 ;    else if(str == "seven")        return 7 ;    else if(str == "eight")        return 8 ;    else if(str == "nine")        return 9 ;    return 0 ;} int main(){    char s[1000] ;    while(gets(s))  	{        string str[100] ;//字符串数组        char *p = NULL ;//p初始值定为空        int count = 0 ;        for(p = strtok(s," ") ; p ; p = strtok(NULL," "))//p = strtok(s," ")将其按碰到第一个空格时拆分，p = strtok(NULL," ")将剩余的后面一部分(NULL)按空格分，直到p为空时            str[count++] = p ;        int a = 0 , b = 0 ;        int i = 0 ;        for( ; str[i] != "+" ; i++) //“+”之前为A		{            int di = digital(str[i]) ;            a = a * 10 ;            a = a + di ;        }        for( ; str[i] != "=" ; i++)//"+"之后“=”之前为B		{            int di = digital(str[i]) ;            b = b * 10 ;            b = b + di ;        }        if(a+b == 0)            return 0 ;        cout << a + b << endl ;    }    return 0;}