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Linux互斥与同步应用(三):posix线程实现单个生产者和单个消费者模型
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在第一节说到了生产者消费者问题,这一节我们来实现这样一个稍作修改的模型: 初始时缓冲区为空,生产者向缓冲区写入数据,消费者在缓冲区为空的情况下睡眠,当生产者写满缓冲区一半之后后通知消费者可以开始消费,生产者开始睡眠,直到消费者消费完缓冲区一半后通知生产者可以开始生产为止,其中生产者和消费者对缓冲区的访问时互斥的。
下面来看一下实现:
#include <stdio.h> #include <pthread.h> #include <unistd.h> #define MAX_BUFFER 6 int buffer = 0; pthread_mutex_t mutex = PTHREAD_MUTEX_INITIALIZER; pthread_cond_t cond_consumer = PTHREAD_COND_INITIALIZER; pthread_cond_t cond_productor = PTHREAD_COND_INITIALIZER; void *consumer_th(void *arg) { for (;;) { pthread_mutex_lock(&mutex); if (buffer <= 0) { printf("=%s->%d=====consumer wait productor to product, start sleep..., buffer=%d\n", __func__, __LINE__, buffer); pthread_cond_wait(&cond_consumer, &mutex);//当消费者发现缓冲区为空时开始睡眠 } buffer--; //消费者消耗一个缓冲区 printf("=%s->%d====consumer consume a buffer, buffer=%d\n", __func__, __LINE__, buffer); if (buffer < MAX_BUFFER/2) { pthread_cond_signal(&cond_productor); //当消费者发现缓冲区不足一半时通知生产者开始生产 printf("=%s->%d====Notify productor...,, buffer: %d\n", __func__, __LINE__, buffer); } pthread_mutex_unlock(&mutex); sleep(3); } return NULL; } void *productor_th(void *arg) { for (;;) { sleep(1); pthread_mutex_lock(&mutex); if (buffer >= MAX_BUFFER) { printf("=%s->%d=====productor wait consumer to consume, start sleep..., buffer=%d\n", __func__, __LINE__, buffer); pthread_cond_wait(&cond_productor, &mutex);//当缓冲区满时,暂停生产 } buffer++;//生产者增加一个缓冲区 printf("=%s->%d====Product add a buffer..., buffer: %d\n", __func__, __LINE__, buffer); if (buffer > MAX_BUFFER/2) { pthread_cond_signal(&cond_consumer);//当缓冲区增加到一半时,通知消费者可以开始消费 printf("=%s->%d====Notify consumer...,, buffer: %d\n", __func__, __LINE__, buffer); } pthread_mutex_unlock(&mutex); } return NULL; } int main(int argc, const char *argv[]) { pthread_t tid_productor, tid_consumer; if (0 != pthread_create(&tid_consumer, NULL, consumer_th, NULL)) { printf("pthread_create failed!\n"); return -1; } if (0 != pthread_create(&tid_productor, NULL, productor_th, NULL)) { printf("pthread_create failed!\n"); return -1; } pthread_join(tid_productor, NULL); pthread_join(tid_consumer, NULL); return 0; }
下面是程序运行输出结果:
=consumer_th->20=====consumer wait productor to product, start sleep..., buffer=0//消费者开始睡眠等待生产者唤醒 =productor_th->54====Product add a buffer..., buffer: 1 =productor_th->54====Product add a buffer..., buffer: 2 =productor_th->54====Product add a buffer..., buffer: 3 =productor_th->54====Product add a buffer..., buffer: 4//生产者开始写缓冲区,当写到第4(超过一半)个通知消费者 =productor_th->58====Notify consumer...,, buffer: 4 =consumer_th->25====consumer consume a buffer, buffer=3//消费者一边消费缓冲区 =productor_th->54====Product add a buffer..., buffer: 4//生产者一边生产缓冲区 =productor_th->58====Notify consumer...,, buffer: 4 =productor_th->54====Product add a buffer..., buffer: 5 =productor_th->58====Notify consumer...,, buffer: 5 =consumer_th->25====consumer consume a buffer, buffer=4 =productor_th->54====Product add a buffer..., buffer: 5 =productor_th->58====Notify consumer...,, buffer: 5 =productor_th->54====Product add a buffer..., buffer: 6 =productor_th->58====Notify consumer...,, buffer: 6 =productor_th->49=====productor wait consumer to consume, start sleep..., buffer=6//当生产者生产缓冲区满时,开始睡眠 =consumer_th->25====consumer consume a buffer, buffer=5 =consumer_th->25====consumer consume a buffer, buffer=4 =consumer_th->25====consumer consume a buffer, buffer=3 =consumer_th->25====consumer consume a buffer, buffer=2//当消费者消费缓冲区到不足一半时,唤醒生产者开始生产 =consumer_th->28====Notify productor...,, buffer: 2 =productor_th->54====Product add a buffer..., buffer: 3 =productor_th->54====Product add a buffer..., buffer: 4 =productor_th->58====Notify consumer...,, buffer: 4 =productor_th->54====Product add a buffer..., buffer: 5 =productor_th->58====Notify consumer...,, buffer: 5 =consumer_th->25====consumer consume a buffer, buffer=4 =productor_th->54====Product add a buffer..., buffer: 5 =productor_th->58====Notify consumer...,, buffer: 5 =productor_th->54====Product add a buffer..., buffer: 6 =productor_th->58====Notify consumer...,, buffer: 6 =productor_th->49=====productor wait consumer to consume, start sleep..., buffer=6
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Linux互斥与同步应用(三):posix线程实现单个生产者和单个消费者模型
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