//返回d=gcd(a,b);和对应于等式ax+by=d中的x,ylong long extend_gcd(long long a,long long b,long long &x,long long &y){    if(a==0&&b==0) return -1;//无最大公约数    if(b==0){x=1;y=0;return a;}    long long d=extend_gcd(b,a%b,y,x);    y-=a/b*x;    return d;}//*********求逆元素*******************//ax = 1(mod n)long long mod_reverse(long long a,long long n){    long long x,y;    long long d=extend_gcd(a,n,x,y);    if(d==1) return (x%n+n)%n;    else return -1;}