首页 > 代码库 > Fri Oct 31 18:00:00 UTC+0800 2008转换为yyyy-mm-dd
Fri Oct 31 18:00:00 UTC+0800 2008转换为yyyy-mm-dd
这个其实网上有很多例子，都是直接用js在前端做了时间处理，我的处理也一样，想要变成2008-3-31，就用下面的js直接可以处理
function Todate(num) { //Fri Oct 31 18:00:00 UTC+0800 2008
num = num + "";
var date = "";
var month = new Array();
month["Jan"] = 1; month["Feb"] = 2; month["Mar"] = 3; month["Apr"] = 4; month["May"] = 5; month["Jun"] = 6;
month["Jul"] = 7; month["Aug"] = 8; month["Sep"] = 9; month["Oct"] = 10; month["Nov"] = 11; month["Dec"] = 12;
var week = new Array();
week["Mon"] = "一"; week["Tue"] = "二"; week["Wed"] = "三"; week["Thu"] = "四"; week["Fri"] = "五"; week["Sat"] = "六"; week["Sun"] = "日";
str = num.split(" ");
date = str[5] + "-";
date = date + month[str[1]] + "-" + str[2];//获取到的年月日，要是想加上时分秒，就date = date + month[str[1]] + "-" + str[2]+ " " + str[3];
return date;
}
我正好做项目，时间要转换成2008-03，我就直接加了个判断
function spliceZero(param)
{
if (param < 10) {
param = "0" + param;
}
return param;
}
/**
* 下面给个完整的例子
*
**/
function Todate(num) { //Fri Oct 31 18:00:00 UTC+0800 2008
if(num!=""){
num = num + "";
var date = "";
var month = new Array();
month["Jan"] = 1; month["Feb"] = 2; month["Mar"] = 3; month["Apr"] = 4; month["May"] = 5; month["Jun"] = 6;
month["Jul"] = 7; month["Aug"] = 8; month["Sep"] = 9; month["Oct"] = 10; month["Nov"] = 11; month["Dec"] = 12;
str = num.split(" ");
date = str[5] + "-";
date = date + spliceZero(month[str[1]]);
return date;
}else{
return "";
}
}
function spliceZero(param)
{
if (param < 10) {
param = "0" + param;
}
return param;
}
Fri Oct 31 18:00:00 UTC+0800 2008转换为yyyy-mm-dd
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