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[C/C++标准库]_[初级]_[构造文件路径(stringByAppendingPathComponent)]


场景:

1. 很多情况下需要通过文件夹和文件名拼接文件路径字符串,每次都需要判断是否需要添加路径分隔符seperator很麻烦,所以可以写一个通用函数.

2. 大多数情况下都是windows使用wstring,mac使用string,所以用模版实现最通用.


函数:

template<class T>
T AppendPathComponent(const T& source,const T& component)
{
	int length = source.length();
	int last = (length)?(length-1):0;

	if(source[last] == 0x5C || source[last] == 0x2F)
	{
		return source+component;
	}else
	{
		T path(source);
		path.resize(length+1);
		path[length] = 0x2F;
		path.append(component);
		return path;
	}
}inline char* Unicode2Ansi(const wchar_t* unicode)  {      int len;      len = WideCharToMultiByte(CP_ACP, 0, unicode, -1, NULL, 0, NULL, NULL);      char *szUtf8 = (char*)malloc(len + 1);      memset(szUtf8, 0, len + 1);      WideCharToMultiByte(CP_ACP, 0,unicode, -1, szUtf8, len, NULL,NULL);      return szUtf8;  } 

调用:

	std::wstring wpath(L"C:\\info/中文");
	std::wstring wpath_1 = AppendPathComponent(wpath,std::wstring(L"info.txt"));
	cout << Unicode2Ansi(wpath_1.c_str()) << endl;

	std::string path("C:\\info");
	std::string path_1 = AppendPathComponent(path,std::string("info.txt"));
	cout << path_1.c_str()<< endl;

输出:

C:\info/中文/info.txt
C:\info/info.txt



[C/C++标准库]_[初级]_[构造文件路径(stringByAppendingPathComponent)]