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HDU1985 Conversions【水题】
Conversions
Time Limit: 1000/500 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 1674 Accepted Submission(s): 986
Conversion between the metric and English measurement systems is relatively simple. Often, it involves either multiplying or dividing by a constant. You must write a program that converts between the following units:
Input
The first line of input contains a single integer N, (1 ≤ N ≤ 1000) which is the number of datasets that follow.Each dataset consists of a single line of input containing a floating point (double precision) number, a space and the unit specification for the measurement to be converted. The unit specification is one of kg, lb, l, or g referring to kilograms, pounds, liters and gallons respectively.
Output
For each dataset, you should generate one line of output with the following values: The dataset number as a decimal integer (start counting at one), a space, and the appropriately converted value rounded to 4 decimal places, a space and the unit specification for the converted value.
Sample Input
5
1 kg
2 l
7 lb
3.5 g
0 l
Sample Output
1 2.2046 lb
2 0.5284 g
3 3.1752 kg
4 13.2489 l
5 0.0000 g
Source
2008 “Shun Yu Cup” Zhejiang Collegiate Programming Contest - Warm Up(1)
题目大意:国际度量制度和英国度量制度之间的转换。
思路:水题。2015年第一道题,希望新的一年继续努力,得到更多的收获。
#include<iostream> #include<string> #include<stdio.h> #include<algorithm> using namespace std; int main() { int N; double a; string s; cin >> N; for(int i = 1; i <= N; ++i) { cin >> a >> s; printf("%d ",i); if(s == "kg") printf("%.4lf lb\n",2.2046*a); else if(s == "l") printf("%.4lf g\n",0.2642*a); else if(s == "lb") printf("%.4lf kg\n",a*0.4536); else if(s == "g") printf("%.4lf l\n",a*3.7854); } return 0; }
HDU1985 Conversions【水题】
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