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HDU 4802

2024-08-10 00:56:58   216人阅读

GPA

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 1861    Accepted Submission(s): 1121


Problem Description
In college, a student may take several courses. for each course i, he earns a certain credit (ci), and a mark ranging from A to F, which is comparable to a score (si), according to the following conversion table
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The GPA is the weighted average score of all courses one student may take, if we treat the credit as the weight. In other words,
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An additional treatment is taken for special cases. Some courses are based on “Pass/Not pass” policy, where stude nts earn a mark “P” for “Pass” and a mark “N” for “Not pass”. Such courses are not supposed to be considered in computation. These special courses must be ignored for computing the correct GPA.
Specially, if a student’s credit in GPA computation is 0, his/her GPA will be “0.00”.

Input
There are several test cases, please process till EOF.
Each test case starts with a line containing one integer N (1 <= N <= 1000), the number of courses. Then follows N lines, each consisting the credit and the mark of one course. Credit is a positive integer and less than 10.

Output
For each test case, print the GPA (rounded to two decimal places) as the answer.

Sample Input
5
2 B
3 D-
2 P
1 F
3 A
2
2 P
2 N
6
4 A
3 A
3 A
4 A
3 A
3 A

Sample Output
2.33
0.00
4.00


Hint
For the first test case:
GPA =(3.0 * 2 + 1.0 * 3 + 0.0 * 1 + 4.0 * 3)/(2 + 3 + 1 + 3) = 2.33

For the second test case: because credit in GPA computation is 0(P/N in additional treatment), so his/her GPA is “0.00”
一遍过的。。简单题，。
#include <stdio.h>
#include <string.h>
int main()
{
    int n;
	while(scanf("%d",&n)!=EOF)
	{
		double a[1005];
		char b[3005][10];
		int i;
		memset(a,0,sizeof(a));
		for(i=1;i<=n;i++)
			scanf("%lf%s",&a[i],b[i]);
		double sum=0;
		double sum1=0;
		for(i=1;i<=n;i++)
		{
			if(strcmp(b[i],"A")==0)
			{
				sum+=a[i]*4.0;
				sum1+=a[i];
			}
			if(strcmp(b[i],"A-")==0)
			{
				sum+=a[i]*3.7;sum1+=a[i];
			}
			if(strcmp(b[i],"B+")==0)
			{
				sum+=a[i]*3.3;sum1+=a[i];
			}
			if(strcmp(b[i],"B")==0)
			{
				sum+=a[i]*3.0;sum1+=a[i];
			}
			if(strcmp(b[i],"B-")==0)
			{
				sum+=a[i]*2.7;sum1+=a[i];
			}
			if(strcmp(b[i],"C+")==0)
			{
				sum+=a[i]*2.3;sum1+=a[i];
			}
			if(strcmp(b[i],"C")==0)
			{
				sum+=a[i]*2.0;sum1+=a[i];
			}
			if(strcmp(b[i],"C-")==0)
			{
				sum+=a[i]*1.7;sum1+=a[i];
			}
			if(strcmp(b[i],"D")==0)
			{
				sum+=a[i]*1.3;sum1+=a[i];
			}
			if(strcmp(b[i],"D-")==0)
			{
				sum+=a[i]*1.0;sum1+=a[i];
			}
			if(strcmp(b[i],"F")==0)
			{
				sum+=0;sum1+=a[i];
			}	
		}
		if(sum1)
		printf("%.2lf\n",sum/sum1);
		else
			printf("0.00\n");
    }
	return 0;
}

怒贴。。

HDU 4802


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