//所谓线索二叉树无非是为了让原本指向NULL的节点指向一个详细的
//已经存在的节点，逻辑上实现指针的无空指向的实现。以下是我中
//序线索二叉树的实现。还是把先序线索二叉树与后序线索分开来写吧。

#include<iostream>
using namespace std;

template<typename Type>
struct Node
{
    Type data;
    bool rflags;//false为线。

    bool lflags;
    Node<Type> *right;
    Node<Type> *left;
    Node(Type d = Type()) :data(d), right(NULL), left(NULL), lflags(false),rflags(false){}
};

template<typename Type>
class MyTree
{
public:
    MyTree() :root(NULL){}
    void Create_lvr_lrv(Type *LVR,Type *LRV)
    {
        int n = strlen(LRV);
        Create_lvr_lrv(root,LVR,LRV,n);
    }
    void Create_Thread_V()//中序构造线索二叉树。
    {
        Node<Type> *pr = NULL;
        Create_Thread_V(root, pr);
        Node<Type> *p = root;
        while (p->right != NULL)
        {
            p = p->right;
        }
        p->right = NULL;
        p->rflags = true;
    }
    void Printf_V()
    {
        Node<Type> *p = root;
        while (p->left != NULL)
        {
            p = p->left;
        }
        Printf_V(p);
    }
private:
    void Printf_V(Node<Type> *t)//中序线索二叉树的打印。
    {
        Node<Type> *p = t;
        while (p != NULL)
        {
            cout << p->data << "  ";
            Node<Type>*m = p->right;
            if (p->rflags != true)
            {
                while (m != NULL && m->lflags != true)
                {
                    m = m->left;
                }
            }
            p=m;
        }
    }
    void Create_Thread_V(Node<Type> *t, Node<Type> *&pr)
    {
        if (t == NULL)
        {
            return;
        }
        Create_Thread_V(t->left, pr);
        if (t->left== NULL)
        {
            t->left = pr;
            t->lflags = true;
        }
        if (pr!=NULL && pr->right ==NULL)
        {
            pr->right = t;
            pr->rflags = true;
        }
        pr = t;
        Create_Thread_V(t->right,pr);
    }

    void Create_lvr_lrv(Node<Type> *&t, Type *LVR, Type *LRV, int n)
    {
        if (n == 0)return;
        int i = 0;
        while (LRV[n - 1] != LVR[i])i++;
        t = new Node<Type>(LRV[n - 1]);
        Create_lvr_lrv(t->right,LVR+i+1,LRV+i,n-i-1);
        //依据中序及后序构造二叉树，此处我选择先构造右子树，然后才构造左子树。
        Create_lvr_lrv(t->left,LVR,LRV,i);
    }

private:
    Node<Type> *root;
};

int main()
{
    char LVR[] = "CBDAFEG";
    char LRV[] = "CDBFGEA";
    MyTree<char> mt;
    mt.Create_lvr_lrv(LVR,LRV);
    mt.Create_Thread_V();
    mt.Printf_V();
    return 0;
}