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LeetCode 1. Two Sum (两数之和)
Given an array of integers, return indices of the two numbers such that they add up to a specific target.
You may assume that each input would have exactly one solution, and you may not use the same element twice.
Example:
Given nums = [2, 7, 11, 15], target = 9, Because nums[0] + nums[1] = 2 + 7 = 9, return [0, 1].
题目标签:Array
这道题目给了我们一个target, 要我们从array里找到两个数相加之和等于这个target。简单粗暴search, 两个for loop,遍历array,每次的 用target 减去当前数字, 在剩下的array里取找。
Java Solution:
Runtime beats 40.09%
完成日期:03/09/2017
关键词:Array
关键点:Brute force search
1 public class Solution 2 { 3 public int[] twoSum(int[] nums, int target) 4 { 5 int [] res = new int[2]; 6 7 for(int i=0; i<nums.length; i++) 8 { 9 int m = target - nums[i];; 10 11 for(int j=i+1; j<nums.length; j++) 12 { 13 if(nums[j] == m) 14 { 15 res[0] = i; 16 res[1] = j; 17 return res; 18 } 19 } 20 21 } 22 23 return res; 24 } 25 }
参考资料:N/A
LeetCode 算法题目列表 - LeetCode Algorithms Questions List
LeetCode 1. Two Sum (两数之和)
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