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用户角色权限 案例
from django.db import models class User(models.Model): """ 用户表 """ username = models.CharField(verbose_name=‘用户名‘, max_length=32) password = models.CharField(verbose_name=‘密码‘, max_length=64) email = models.EmailField(verbose_name=‘邮箱‘) def __str__(self): return self.username class Role(models.Model): """ 角色表 """ caption = models.CharField(verbose_name=‘角色‘, max_length=32) def __str__(self): return self.caption class User2Role(models.Model): """ 用户角色关系表 """ user = models.ForeignKey(User, verbose_name=‘用户‘, related_name=‘roles‘) role = models.ForeignKey(Role, verbose_name=‘角色‘, related_name=‘users‘) def __str__(self): return ‘%s-%s‘ % (self.user.username, self.role.caption,) class Menu(models.Model): """ 菜单表 """ caption = models.CharField(verbose_name=‘菜单名称‘, max_length=32) parent = models.ForeignKey(‘self‘, verbose_name=‘父菜单‘, related_name=‘p‘, null=True, blank=True) def __str__(self): prev = "" parent = self.parent while True: if parent: prev = prev + ‘-‘ + str(parent.caption) parent = parent.parent else: break return ‘%s-%s‘ % (prev, self.caption,) class Permission(models.Model): """ 权限 """ caption = models.CharField(verbose_name=‘权限‘, max_length=32) url = models.CharField(verbose_name=‘URL正则‘, max_length=128) menu = models.ForeignKey(Menu, verbose_name=‘所属菜单‘, related_name=‘permissions‘,null=True,blank=True) def __str__(self): return "%s-%s" % (self.caption, self.url,) class Action(models.Model): """ 操作:增删改查 """ caption = models.CharField(verbose_name=‘操作标题‘, max_length=32) code = models.CharField(verbose_name=‘方法‘, max_length=32) def __str__(self): return self.caption class Permission2Action2Role(models.Model): """ 权限操作关系表 """ permission = models.ForeignKey(Permission, verbose_name=‘权限URL‘, related_name=‘actions‘) action = models.ForeignKey(Action, verbose_name=‘操作‘, related_name=‘permissions‘) role = models.ForeignKey(Role, verbose_name=‘角色‘, related_name=‘p2as‘) class Meta: unique_together = ( (‘permission‘, ‘action‘, ‘role‘), ) def __str__(self): return "%s-%s-%s" % (self.permission, self.action, self.role,) python3 manage.py startapp app02
用户角色权限 案例
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