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hdu3555Bomb(数位dp)

2024-10-27 18:42:39   207人阅读

Bomb

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 131072/65536 K (Java/Others)
Total Submission(s): 18659    Accepted Submission(s): 6891


Problem Description
The counter-terrorists found a time bomb in the dust. But this time the terrorists improve on the time bomb. The number sequence of the time bomb counts from 1 to N. If the current number sequence includes the sub-sequence "49", the power of the blast would add one point.
Now the counter-terrorist knows the number N. They want to know the final points of the power. Can you help them?
 

 

Input
The first line of input consists of an integer T (1 <= T <= 10000), indicating the number of test cases. For each test case, there will be an integer N (1 <= N <= 2^63-1) as the description.

The input terminates by end of file marker.
 

 

Output
For each test case, output an integer indicating the final points of the power.
 

 

Sample Input
3150500
 

 

Sample Output
0115
Hint
From 1 to 500, the numbers that include the sub-sequence "49" are "49","149","249","349","449","490","491","492","493","494","495","496","497","498","499",so the answer is 15.
 

 

Author
fatboy_cw@WHU
 

 

Source
2010 ACM-ICPC Multi-University Training Contest（12）——Host by WHU 
 
思路同hdu2089 http://www.cnblogs.com/L-Memory/p/7189656.html
 
#include<iostream>#include<cstdio>#include<cstring>using namespace std;long long f[20][20],dig[20];long long ans,len,n,m,t;void init(){    ans=0;len=0;    memset(f,0,sizeof f);    f[0][0]=1;    for(long long i=1;i<=20;i++)      for(long long j=0;j<10;j++)        for(long long k=0;k<10;k++)          if(!(j==4 && k==9)) f[i][j]+=f[i-1][k];}long long solve(long long x){    while(x)    {        dig[++len]=x%10;        x/=10;    }dig[len+1]=0;    for(long long i=len;i;i--)    {        for(long long j=0;j<dig[i];j++)          if(!(dig[i+1]==4 && j==9)) ans+=f[i][j];        if(dig[i]==9 && dig[i+1]==4) break;    }return ans;}int main(){    cin>>t;    while(t--)    {        cin>>n;        init();        cout<<n+1-solve(n+1)<<endl;    }    return 0;}

 

hdu3555Bomb(数位dp)


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