Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order.

You may assume no duplicates in the array.

Here are few examples.
[1,3,5,6], 5 → 2
[1,3,5,6], 2 → 1
[1,3,5,6], 7 → 4
[1,3,5,6], 0 → 0

其实就是个二分

class Solution {public:    int searchInsert(vector<int>& nums, int target) {        int x = lower_bound(nums.begin(), nums.end(), target) - nums.begin();        return x;    }};

35. Search Insert Position