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python hook监听事件
python hook监听事件
作者:vpoet
日期:夏季
# -*- coding: utf-8 -*- # # by oldj http://oldj.net/ # import pythoncom import pyHook def onm ouseEvent(event): # 监听鼠标事件 print "MessageName:",event.MessageName print "Message:", event.Message print "Time:", event.Time print "Window:", event.Window print "WindowName:", event.WindowName print "Position:", event.Position print "Wheel:", event.Wheel print "Injected:", event.Injected print"---" # 返回 True 以便将事件传给其他处理程序 # 注意。这儿假设返回 False ,则鼠标事件将被全部拦截 # 也就是说你的鼠标看起来会僵在那儿。似乎失去响应了 return True def onKeyboardEvent(event): # 监听键盘事件 print "MessageName:", event.MessageName print "Message:", event.Message print "Time:", event.Time print "Window:", event.Window print "WindowName:", event.WindowName print "Ascii:", event.Ascii, chr(event.Ascii) print "Key:", event.Key print "KeyID:", event.KeyID print "ScanCode:", event.ScanCode print "Extended:", event.Extended print "Injected:", event.Injected print "Alt", event.Alt print "Transition", event.Transition print "---" # 同鼠标事件监听函数的返回值 return True def main(): # 创建一个“钩子”管理对象 hm = pyHook.HookManager() # 监听全部键盘事件 hm.KeyDown = onKeyboardEvent # 设置键盘“钩子” hm.HookKeyboard() # 监听全部鼠标事件 hm.MouseAll = onm ouseEvent # 设置鼠标“钩子” hm.HookMouse() # 进入循环。如不手动关闭,程序将一直处于监听状态 pythoncom.PumpMessages() if __name__ == "__main__": main()
python hook监听事件
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