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461. Hamming Distance
The Hamming distance between two integers is the number of positions at which the corresponding bits are different.
Given two integers x
and y
, calculate the Hamming distance.
Note:
0 ≤ x
, y
< 231.
Example:
Input: x = 1, y = 4Output: 2Explanation:1 (0 0 0 1)4 (0 1 0 0) ? ?The above arrows point to positions where the corresponding bits are different.
统计一个二进制数中 1 的个数。之前在编程之美中看到 用这种方法判断 :x = x&( x - 1)
class Solution {public: int hammingDistance(int x, int y) { int xy=x^y; int dis=0; while(xy) { xy=xy&(xy-1); dis++; } return dis; }};
461. Hamming Distance
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