IF OBJECT_ID(‘[tb]‘) IS NOT NULL DROP TABLE [tb]
GO
create table tb(姓名 varchar(10) , 课程 varchar(10) , 分数 int)
insert into tb values(‘张三‘ , ‘语文‘ , 74)
insert into tb values(‘张三‘ , ‘数学‘ , 83)
insert into tb values(‘张三‘ , ‘物理‘ , 93)
insert into tb values(‘李四‘ , ‘语文‘ , 74)
insert into tb values(‘李四‘ , ‘数学‘ , 84)
insert into tb values(‘李四‘ , ‘物理‘ , 94)
go

--SQL SERVER 2000 动态SQL,指课程不止语文、数学、物理这三门课程。(以下同)
declare @sql varchar(8000)
set @sql = ‘select 姓名 ‘
select @sql = @sql + ‘ , max(case 课程 when ‘‘‘ + 课程 + ‘‘‘ then 分数 else 0 end) [‘ + 课程 + ‘]‘
from (select distinct 课程 from tb) as a
set @sql = @sql + ‘ from tb group by 姓名‘
exec(@sql)
--通过动态构建@sql，得到如下脚本
select 姓名 as 姓名 ,
  max(case 课程 when ‘语文‘ then 分数 else 0 end) 语文,
  max(case 课程 when ‘数学‘ then 分数 else 0 end) 数学,
  max(case 课程 when ‘物理‘ then 分数 else 0 end) 物理
from tb
group by 姓名

--SQL SERVER 2005 动态SQL。
declare @sql varchar(8000)
select @sql = isnull(@sql + ‘],[‘ , ‘‘) + 课程 from tb group by 课程
set @sql = ‘[‘ + @sql + ‘]‘
exec (‘select * from (select * from tb) a pivot (max(分数) for 课程 in (‘ + @sql + ‘)) b‘)
--得到SQL SERVER 2005 静态SQL。
select * from (select * from tb) a pivot (max(分数) for 课程 in (语文,数学,物理)) b

--SQL SERVER 2000 静态SQL。
select 姓名 姓名,
  max(case 课程 when ‘语文‘ then 分数 else 0 end) 语文,
  max(case 课程 when ‘数学‘ then 分数 else 0 end) 数学,
  max(case 课程 when ‘物理‘ then 分数 else 0 end) 物理,
  cast(avg(分数*1.0) as decimal(18,2)) 平均分,
  sum(分数) 总分
from tb
group by 姓名

--SQL SERVER 2000 动态SQL。
declare @sql varchar(8000)
set @sql = ‘select 姓名 ‘
select @sql = @sql + ‘ , max(case 课程 when ‘‘‘ + 课程 + ‘‘‘ then 分数 else 0 end) [‘ + 课程 + ‘]‘
from (select distinct 课程 from tb) as a
set @sql = @sql + ‘ , cast(avg(分数*1.0) as decimal(18,2)) 平均分 , sum(分数) 总分 from tb group by 姓名‘
exec(@sql)

--SQL SERVER 2005 静态SQL。
select m.* , n.平均分 , n.总分 from
(select * from (select * from tb) a pivot (max(分数) for 课程 in (语文,数学,物理)) b) m,
(select 姓名 , cast(avg(分数*1.0) as decimal(18,2)) 平均分 , sum(分数) 总分 from tb group by 姓名) n
where m.姓名 = n.姓名

--SQL SERVER 2005 动态SQL。
declare @sql varchar(8000)
select @sql = isnull(@sql + ‘,‘ , ‘‘) + 课程 from tb group by 课程
exec (‘select m.* , n.平均分 , n.总分 from
(select * from (select * from tb) a pivot (max(分数) for 课程 in (‘ + @sql + ‘)) b) m ,
(select 姓名 , cast(avg(分数*1.0) as decimal(18,2)) 平均分 , sum(分数) 总分 from tb group by 姓名) n
where m.姓名 = n.姓名‘)

if object_id(‘tb1‘) is not null drop table tb1
go
CREATE table tb1 --数据表
(
cpici varchar(10) not null,
cname varchar(10) not null,
cvalue int null
)
--插入测试数据
INSERT INTO tb1 values(‘T501‘,‘x1‘,31)
INSERT INTO tb1 values(‘T501‘,‘x1‘,33)
INSERT INTO tb1 values(‘T501‘,‘x1‘,5)

INSERT INTO tb1 values(‘T502‘,‘x1‘,3)
INSERT INTO tb1 values(‘T502‘,‘x1‘,22)
INSERT INTO tb1 values(‘T502‘,‘x1‘,3)

INSERT INTO tb1 values(‘T503‘,‘x1‘,53)
INSERT INTO tb1 values(‘T503‘,‘x1‘,44)
INSERT INTO tb1 values(‘T503‘,‘x1‘,50)
INSERT INTO tb1 values(‘T503‘,‘x1‘,23)


--在sqlserver2000里需要用自增辅助
alter table tb1 add id int identity
go
declare @s varchar(8000)
set @s=‘select cpici ‘
select @s=@s+‘,max(case when rn=‘+ltrim(rn)+‘ then cvalue end) as cvlue‘+ltrim(rn)
from (select distinct rn from (select rn=(select count(1) from tb1 where cpici=t.cpici and id<=t.id) from tb1 t)a)t
set @s=@s+‘ from (select rn=(select count(1) from tb1 where cpici=t.cpici and id<=t.id),* from tb1 t
) t group by cpici‘

exec(@s)
go
alter table tb1 drop column id

--再2005就可以用row_number
declare @s varchar(8000)
set @s=‘select cpici ‘
select @s=@s+‘,max(case when rn=‘+ltrim(rn)+‘ then cvalue end) as cvlue‘+ltrim(rn)
from (select distinct rn from (select rn=row_number()over(partition by cpici order by getdate()) from tb1)a)t
set @s=@s+‘ from (select rn=row_number()over(partition by cpici order by getdate()),* from tb1
) t group by cpici‘

exec(@s)

--测试用
IF OBJECT_ID(‘[tb]‘) IS NOT NULL DROP TABLE [tb]
GO
create table tb(电话号码 varchar(15), 通话时长 int ,行业 varchar(10))
insert tb
select ‘13883633601‘, 10 ,‘餐饮‘ union all
select ‘18689704236‘, 20 ,‘物流‘ union all
select ‘13883633601‘, 20 ,‘物流‘ union all
select ‘13883633601‘, 20 ,‘汽车‘ union all
select ‘18689704236‘, 20 ,‘医疗‘ union all
select ‘18689704236‘, 20 ,‘it‘ union all
select ‘18689704236‘, 20 ,‘汽车‘ union all
select ‘13883633601‘, 50 ,‘餐饮‘
go

declare @sql varchar(8000)
set @sql=‘select 电话号码,sum(通话时长) 通话总和‘
select @sql=@sql+‘,max(case when rowid=‘+ltrim(rowid)+‘ then 行业 else ‘‘‘‘ end) as [行业‘+ltrim(rowid)+‘]‘
from (select distinct rowid from (select (select count(distinct 行业) from tb where 电话号码=t.电话号码 and 行业<=t.行业) rowid
from tb t) a) b
set @sql=@sql+‘ from ( select * , (select count(distinct 行业) from tb where 电话号码=t.电话号码 and 行业<=t.行业) rowid
from tb t ) t group by 电话号码‘
exec(@sql)

if object_id(‘[tb]‘) is not null drop table [tb]
go  
create table [tb]([姓名] varchar(1),[部门] varchar(4),[学历] varchar(4),[出生年月] datetime)
insert [tb]
select ‘A‘,‘后勤‘,‘高中‘,‘1986-1-1‘ union all
select ‘B‘,‘后勤‘,‘初中‘,‘1984-3-7‘ union all
select ‘C‘,‘管理‘,‘本科‘,‘1987-2-1‘ union all
select ‘D‘,‘操作‘,‘专科‘,‘1976-2-1‘ union all
select ‘E‘,‘操作‘,‘专科‘,‘1943-2-1‘  
go


GO
if object_id(‘GetGroupByCol‘) is not null drop proc GetGroupByCol
go
create  PROCEDURE [dbo].[GetGroupByCol]
@colm nvarchar(100)
  AS
declare @sql varchar(4000)

set @sql=‘
declare @sql varchar(8000)
set @sql=‘‘select 部门‘‘
select @sql =@sql+ ‘‘, sum(case ltrim(‘+@colm+‘) when ‘‘‘‘‘‘+ltrim(‘ + @colm + ‘)+‘‘‘‘‘‘ then 1 else 0 end)
[‘‘+ltrim(‘ + @colm + ‘)+‘‘]‘‘ from (select distinct ‘+@colm+‘ from tb where ‘+@colm+‘ is not null) as a
set @sql = @sql + ‘‘ from tb group by 部门‘‘
exec(@sql)‘

exec(@sql)
GO

exec GetGroupByCol N‘学历‘
exec GetGroupByCol N‘出生年月‘
exec GetGroupByCol N‘姓名‘