用栈去判断()，剩余的暴力判断

如果(xx)成立，就令(xx)=11..11 视为1个表达式。

注意以下数据

() no

0|，0||，0||1，0|* no

)( no

#include<cstdio>
#include<cstring>
#include<cstdlib>
#include<algorithm>
#include<functional>
#include<iostream>
#include<cmath>
#include<cctype>
#include<ctime>
using namespace std;
#define For(i,n) for(int i=1;i<=n;i++)
#define Fork(i,k,n) for(int i=k;i<=n;i++)
#define Rep(i,n) for(int i=0;i<n;i++)
#define ForD(i,n) for(int i=n;i;i--)
#define RepD(i,n) for(int i=n;i>=0;i--)
#define Forp(x) for(int p=pre[x];p;p=next[p])
#define Forpiter(x) for(int &p=iter[x];p;p=next[p])  
#define Lson (x<<1)
#define Rson ((x<<1)+1)
#define MEM(a) memset(a,0,sizeof(a));
#define MEMI(a) memset(a,127,sizeof(a));
#define MEMi(a) memset(a,128,sizeof(a));
#define INF (2139062143)
#define F (100000007)
#define MAXN (1000+10)
long long mul(long long a,long long b){return (a*b)%F;}
long long add(long long a,long long b){return (a+b)%F;}
long long sub(long long a,long long b){return (a-b+(a-b)/F*F+F)%F;}
typedef long long ll;
char s[MAXN];
int n,st[MAXN],tail;
bool check2(int a,int b)
{
	bool now=0;
	Fork(j,a+1,b-1)
	{
		if (s[j]=='0') now=1;
		else if (s[j]=='*') 
		{
			if (now==0) return 0;
		} 
		else if (s[j]=='|')
		{
			if (now==0) return 0;
			now=0;
		}
	}
	if (s[b-1]=='|') return 0;
	Fork(j,a,b) s[j]='0';
	return 1;	
}
bool check3(int a,int b)
{
	bool now=0;
	Fork(j,a,b)
	{
		if (s[j]=='0') now=1;
		else if (s[j]=='*') 
		{
			if (now==0) return 0;
		} 
		else if (s[j]=='|')
		{
			if (now==0) return 0;
			now=0;
		}
	}
	if (s[b]=='|') return 0;
	return 1;	
}
bool check()
{
	tail=0;
	Rep(i,n)
		if(s[i]=='1'||s[i]=='0') s[i]='0';
		else if (s[i]!='('&&s[i]!=')'&&s[i]!='*'&&s[i]!='|') return 0;
	
	Rep(i,n)
	{
		if (s[i]=='(') st[++tail]=i;
		else if (s[i]==')') 
		{
			if (!tail) return 0;
			int a=st[tail--],b=i;
			if (a+1==b) return 0;
			if (!check2(a,b)) return 0; 
		}
	}
	if (tail) return 0;
	if (!check3(0,n-1)) return 0; 
	return 1;	
}
int main()
{
//	freopen("regular.in","r",stdin);
	while(scanf("%s",s)==1)
	{
		n=strlen(s);
		if (n==0) break;
		
		
		if (check()) cout<<"yes"<<endl;
		else cout<<"no"<<endl;
		
	}
	
	
	return 0;
}

hihoCoder 挑战赛7(正则表达式-栈)