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高精度模板

#include<iostream>
#include<cstring>
#include<iomanip>
#include<algorithm>
#include<cstdlib>
#include<cstdio>
using namespace std;

#define MAXN 9999
#define MAXSIZE 10000
#define DLEN 4

class BigNum{
private:
    int a[MAXSIZE];    //可以控制大数的位数
    int len;           //大数长度
    int is;
public:
    BigNum(){len = 1 ; memset(a,0,sizeof(a)); }   //构造函数
    BigNum(const int);       //将一个int类型的变量转化为大数
    BigNum(const char*);     //将一个字符串类型的变量转化为大数
    BigNum(const BigNum &);  //拷贝构造函数
    BigNum &operator = (const BigNum &);   //重载赋值运算符,大数之间进行赋值运算

    friend istream& operator >> (istream&,  BigNum&);   //重载输入运算符
    friend ostream& operator << (ostream&,  BigNum&);   //重载输出运算符

    BigNum operator + (const BigNum &) const;   //重载加法运算符,两个大数之间的相加运算
    BigNum operator - (const BigNum &) const;   //重载减法运算符,两个大数之间的相减运算
    BigNum operator * (const BigNum &) const;   //重载乘法运算符,两个大数之间的相乘运算
    BigNum operator / (const int    &) const;   //重载除法运算符,大数对一个整数进行相除运算

    BigNum operator ^ (const int    &) const;   //大数的n次方运算
    int    operator % (const int    &) const;   //大数对一个int类型的变量进行取模运算
    bool   operator > (const BigNum & T)const;  //大数和另一个大数的大小比较
    bool   operator > (const int    & t)const;  //大数和一个int类型的变量的大小比较

    void print();       //输出大数
};
BigNum::BigNum(const int b){    //将一个int类型的变量转化为大数
    int c,d = b;
    len = 0;
    if(d < 0){
        d = -d;
        is = 1;
    }
    memset(a,0,sizeof(a));
    while(d > MAXN){
        c = d - (d / (MAXN + 1)) * (MAXN + 1);
        d = d / (MAXN + 1);
        a[len ++] = c;
    }
    a[len ++] = d;
}
BigNum::BigNum(const char*s){    //将一个字符串类型的变量转化为大数
    int t , k;
    memset(a , 0 , sizeof(a));
    int l=strlen(s);
    if(s[0] == -) is = 1;
    else is = 0;
    len=l / DLEN;
    if(l % DLEN) len ++;
    int index = 0;
    for(int i = l - 1 ; i >= is ; i -= DLEN){
        t = 0;
        k = i - DLEN + 1;
        if(k < is) k = is;
        for(int j = k ; j <= i ; ++ j) t = t * 10 + s[j] - 0;
        a[index ++] = t;
    }
}
BigNum::BigNum(const BigNum & T) : len(T.len){  //拷贝构造函数
    is = T.is;
    memset(a,0,sizeof(a));
    for(int i = 0 ; i < len ; i++) a[i] = T.a[i];
}
BigNum & BigNum::operator = (const BigNum & n){  //重载赋值运算符,大数之间进行赋值运算
    len = n.len;
    is = n.is;
    memset(a,0,sizeof(a));
    for(int i = 0 ; i < len ; i++) a[i] = n.a[i];
    return *this;
}
istream& operator >> (istream & in,  BigNum & b){   //重载输入运算符
    char ch[MAXSIZE << 2];
    in >> ch;
    int l = strlen(ch);
    if(ch[0] == -) b.is = 1;
    else b.is = 0;
    int count = 0 , sum = 0;
    int i = -1;
    for(i = l-1 ; i >= b.is;){
        sum = 0;
        int t = 1;
        for(int j = 0 ; j < 4 && i >= b.is ; ++ j , -- i , t *= 10){
            sum += (ch[i]-0) * t;
        }
        b.a[count]=sum;
        count++;
    }
    b.len = count;
    return in;

}
/*ostream& operator<<(ostream& out,  BigNum& b)   //重载输出运算符
{
    int i;
    cout << b.a[b.len - 1];
    for(i = b.len - 2 ; i >= 0 ; i--)
    {
        cout.width(DLEN);
        cout.fill(‘0‘);
        cout << b.a[i];
    }
    return out;
}*/

BigNum BigNum::operator + (const BigNum & T) const{   //两个大数之间的相加运算
    if(is == T.is){
        BigNum t(*this);
        int big = T.len > len ? T.len : len;    //位数
        for(int i = 0 ; i < big ; ++ i){
            t.a[i] += T.a[i];
            if(t.a[i] > MAXN){
                t.a[i + 1]++;
                t.a[i] -= MAXN + 1;
            }
        }
        if(t.a[big] != 0) t.len = big + 1;
        else t.len = big;
        if(T.is && is) t.is = 1;
        else t.is = 0;
        return t;
    }
    else{
        if(T.is){
            BigNum test = T;
            test.is = 0;
            BigNum t(*this);
            BigNum ans = t - test;
            return ans;
        }
        else{
            BigNum t(*this);
            t.is = 0;
            BigNum ans = T - t;
            t.is = 1;
            return ans;
        }
    }
}
BigNum BigNum::operator - (const BigNum & T) const   //两个大数之间的相减运算
{
    if(T.is != is){
        if(T.is){
            BigNum test = T;
            test.is = 0;
            BigNum t(*this);
            BigNum ans = t + test;
            return ans;
        }
        else{
            BigNum t(*this);
            t.is = 0;
            BigNum ans = t + T;
            ans.is = 1;
            t.is = 1;
            return ans;
        }
    }
    bool flag;
    BigNum t1,t2;
    if(*this>T){
        t1=*this;
        t2=T;
        flag=0;
    }
    else{
        t1=T;
        t2=*this;
        flag=1;
    }
    int big=t1.len;
    for(int i = 0 ; i < big ; ++ i){
        if(t1.a[i] < t2.a[i]){
            int j = i + 1;
            while(t1.a[j] == 0) ++ j;
            t1.a[j --] --;
            while(j > i) t1.a[j--] += MAXN;
            t1.a[i] += MAXN + 1 - t2.a[i];
        }
        else t1.a[i] -= t2.a[i];
    }
    t1.len = big;
    while(t1.a[t1.len - 1] == 0 && t1.len > 1){
        -- t1.len;
        -- big;
    }
    if(flag) t1.is = 1;
    else t1.is = 0;
    return t1;
}

BigNum BigNum::operator*(const BigNum & T) const{  //两个大数之间的相乘运算
    BigNum ret;
    int i,j,up;
    int temp,temp1;
    for(i = 0 ; i < len ; i++)
    {
        up = 0;
        for(j = 0 ; j < T.len ; j++)
        {
            temp = a[i] * T.a[j] + ret.a[i + j] + up;
            if(temp > MAXN)
            {
                temp1 = temp - temp / (MAXN + 1) * (MAXN + 1);
                up = temp / (MAXN + 1);
                ret.a[i + j] = temp1;
            }
            else
            {
                up = 0;
                ret.a[i + j] = temp;
            }
        }
        if(up != 0)
            ret.a[i + j] = up;
    }
    ret.len = i + j;
    while(ret.a[ret.len - 1] == 0 && ret.len > 1)
        ret.len--;
    ret.is = is == T.is ? 0 : 1;
    return ret;
}
BigNum BigNum::operator/(const int & b) const   //大数对一个整数进行相除运算
{
    BigNum ret;
    int i,down = 0;
    for(i = len - 1 ; i >= 0 ; i--){
        ret.a[i] = (a[i] + down * (MAXN + 1)) / b;
        down = a[i] + down * (MAXN + 1) - ret.a[i] * b;
    }
    ret.len = len;
    while(ret.a[ret.len - 1] == 0 && ret.len > 1) ret.len--;
    int testis = b >= 0 ? 0 : 1;
    ret.is = testis == is ? 0 : 1;
    return ret;
}
int BigNum::operator % (const int & b) const{   //大数对一个int类型的变量进行取模运算
    int i,d=0;
    for (i = len-1; i>=0; i--) d = ((d * (MAXN+1))% b + a[i])% b;
    return d;
}
BigNum BigNum::operator ^ (const int & n) const    //大数的n次方运算
{
    BigNum t,ret(1);
    if(n < 0) exit(-1);
    if(n == 0) return 1;
    if(n == 1) return *this;
    int m = n;
    int i;
    while(m > 1){
        t = *this;
        for(i = 1 ; (i << 1) <= m; i <<= 1) t = t * t;
        m -= i;
        ret = ret * t;
        if(m == 1) ret = ret * (*this);
    }
    return ret;
}
bool BigNum::operator>(const BigNum & T) const{   //大数和另一个大数的大小比较
    if(is && !T.is) return false;
    if(!is && T.is) return true;
    if(len > T.len){
        if(!T.is && !is) return true;
        else return false;
    }
    else if(len == T.len){
        int ln = len - 1;
        while(a[ln] == T.a[ln] && ln >= 0)
            ln --;
        if(ln >= 0 && a[ln] > T.a[ln]){
            if(!T.is && !is) return true;
            else return false;
        }
        else{
            if(!T.is && !is) return false;
            else return true;
        }
    }
    else{
        if(!T.is && !is) return false;
        else return true;
    }
}
bool BigNum::operator >(const int & t) const{    //大数和一个int类型的变量的大小比较
    BigNum b(t);
    return *this>b;
}

void BigNum::print(){    //输出大数
    int i;
    if(is) printf("-");
    printf("%d",a[len-1]);
    for(i = len - 2 ; i >= 0 ; i--) printf("%04d",a[i]);
    printf("\n");
}
char s[100010];
int main()
{
    int text;
    cin>>text;
    while(text--)
    {
        BigNum ans(0);
        while(~scanf("%s" , s)){
            ans = ans + BigNum(s);
            if(strlen(s) == 1 && s[0] == 0) break;
        }
        ans.print();
        if(text) printf("\n");
    }
    return 0;
}

 

高精度模板