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Valid Parentheses
Given a string containing just the characters ‘(‘
, ‘)‘
, ‘{‘
, ‘}‘
, ‘[‘
and ‘]‘
, determine if the input string is valid.
The brackets must close in the correct order, "()"
and "()[]{}"
are all valid but "(]"
and "([)]"
are not.
1 public class Solution { 2 public boolean isValid(String s) { 3 Stack stack=new Stack(); 4 for(int i=0;i<s.length();i++) 5 { 6 char ch=s.charAt(i); 7 if(ch==‘(‘||ch==‘[‘||ch==‘{‘) 8 { 9 stack.push(ch);10 }11 else12 {13 if(!stack.isEmpty())14 {15 if(isEqual((char)stack.peek(),ch))16 {17 stack.pop();18 }19 else20 return false;21 }22 else23 return false;24 }25 }26 return stack.isEmpty()?true:false;27 }28 public boolean isEqual(char c1,char c2)29 {30 if(c1==‘[‘&&c2==‘]‘)return true;31 else if(c1==‘(‘&&c2==‘)‘)return true;32 else if(c1==‘{‘&&c2==‘}‘)return true;33 return false;34 }35 }
Valid Parentheses
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