首页 > 代码库 > WebApi传递JSON参数

WebApi传递JSON参数

开发过程中经常进行JSON的传递,在WebApi中传递JSON字串时,会发现服务器端接收到不参数值,看下面代码

服务端:

public void Post([FromBody]string value)        {            LoggerHelper.Info("Post:{0}", value);        }

客户端:

HttpClient client = new HttpClient();            client.DefaultRequestHeaders.Accept.Add(new MediaTypeWithQualityHeaderValue("application/json"));            string url = "http://api.oa.com/api/Test/Post";            var json = "{ \"Name\": \"Test\" }";            var httpContent = new StringContent(json, Encoding.UTF8);            httpContent.Headers.ContentType = new MediaTypeHeaderValue("application/json");            var response = client.PostAsJsonAsync(url, httpContent).Result;            if (!response.IsSuccessStatusCode)            {                Response.Write(string.Format("{0} ({1})", (int)response.StatusCode, response.ReasonPhrase));            }

运行客户端,查看服务端的日志,结果为“Post:”,调用成功,但参数接收失败。

查了些资料,显示WebApi不支持JSON字串做为简单参数传递,既然如此就将JSON字串做为复杂类型进行传,对代码稍做调整,服务端接收JObject参数:

public void Post([FromBody]JObject value)        {                        LoggerHelper.Info("Post:{0}", value.ToString());        }

客户端:

HttpClient client = new HttpClient();            client.DefaultRequestHeaders.Accept.Add(new MediaTypeWithQualityHeaderValue("application/json"));            string url = "http://api.oa.com/api/Test/Post";            var json = "{ \"Name\": \"Test\" }";            var jObject = JObject.Parse(json);            var response = client.PostAsJsonAsync(url, jObject).Result;            if (!response.IsSuccessStatusCode)            {                Response.Write(string.Format("{0} ({1})", (int)response.StatusCode, response.ReasonPhrase));            }

运行客户端,再次查看服务端的日志,结果为:

Post:{
"Name": "Test"
},参数传递成功

WebApi传递JSON参数