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Linux操作系统下oracle数据库中不存在scott用户的解决方案
① 以‘sys‘用户登录到数据库中,输入select * from dba_users;查看一下是否存在scott用户,如下图所示:
如上图所示,scott用户的确不存在。
② 由于操作系统是Linux,则用xshell登录Linux界面,切换到oracle用户,如下图所示,找到如下目录,看是否存在scott.sql文件:
/home/oracle/product/ora11g/rdbms/admin -- 该路径视自己的实际路径为准
如果存在,则以sys用户登录数据库,并执行如下语句:
如果不存在,则在/home/oracle/product/ora11g/rdbms/admin下创建scott.sql文件,并保存如下代码:
Rem Copyright (c) 1990 by Oracle Corporation
Rem NAME
REM UTLSAMPL.SQL
Rem FUNCTION
Rem NOTES
Rem MODIFIED
Rem gdudey 06/28/95 - Modified for desktop seed database
Rem glumpkin 10/21/92 - Renamed from SQLBLD.SQL
Rem blinden 07/27/92 - Added primary and foreign keys to EMP and DEPT
Rem rlim 04/29/91 - change char to varchar2
Rem mmoore 04/08/91 - use unlimited tablespace priv
Rem pritto 04/04/91 - change SYSDATE to 13-JUL-87
Rem Mendels 12/07/90 - bug 30123;add to_date calls so language independent
Rem
rem
rem $Header: utlsampl.sql 7020100.1 94/09/23 22:14:24 cli Generic<base> $ sqlbld.sql
rem
SET TERMOUT OFF
SET ECHO OFF
rem CONGDON Invoked in RDBMS at build time. 29-DEC-1988
rem OATES: Created: 16-Feb-83
GRANT CONNECT,RESOURCE,UNLIMITED TABLESPACE TO SCOTT IDENTIFIED BY TIGER;
ALTER USER SCOTT DEFAULT TABLESPACE USERS;
ALTER USER SCOTT TEMPORARY TABLESPACE TEMP;
CONNECT SCOTT/TIGER
DROP TABLE DEPT;
CREATE TABLE DEPT
(DEPTNO NUMBER(2) CONSTRAINT PK_DEPT PRIMARY KEY,
DNAME VARCHAR2(14) ,
LOC VARCHAR2(13) ) ;
DROP TABLE EMP;
CREATE TABLE EMP
(EMPNO NUMBER(4) CONSTRAINT PK_EMP PRIMARY KEY,
ENAME VARCHAR2(10),
JOB VARCHAR2(9),
MGR NUMBER(4),
HIREDATE DATE,
SAL NUMBER(7,2),
COMM NUMBER(7,2),
DEPTNO NUMBER(2) CONSTRAINT FK_DEPTNO REFERENCES DEPT);
INSERT INTO DEPT VALUES
(10,‘ACCOUNTING‘,‘NEW YORK‘);
INSERT INTO DEPT VALUES (20,‘RESEARCH‘,‘DALLAS‘);
INSERT INTO DEPT VALUES
(30,‘SALES‘,‘CHICAGO‘);
INSERT INTO DEPT VALUES
(40,‘OPERATIONS‘,‘BOSTON‘);
INSERT INTO EMP VALUES
(7369,‘SMITH‘,‘CLERK‘,7902,to_date(‘17-12-1980‘,‘dd-mm-yyyy‘),800,NULL,20);
INSERT INTO EMP VALUES
(7499,‘ALLEN‘,‘SALESMAN‘,7698,to_date(‘20-2-1981‘,‘dd-mm-yyyy‘),1600,300,30);
INSERT INTO EMP VALUES
(7521,‘WARD‘,‘SALESMAN‘,7698,to_date(‘22-2-1981‘,‘dd-mm-yyyy‘),1250,500,30);
INSERT INTO EMP VALUES
(7566,‘JONES‘,‘MANAGER‘,7839,to_date(‘2-4-1981‘,‘dd-mm-yyyy‘),2975,NULL,20);
INSERT INTO EMP VALUES
(7654,‘MARTIN‘,‘SALESMAN‘,7698,to_date(‘28-9-1981‘,‘dd-mm-yyyy‘),1250,1400,30);
INSERT INTO EMP VALUES
(7698,‘BLAKE‘,‘MANAGER‘,7839,to_date(‘1-5-1981‘,‘dd-mm-yyyy‘),2850,NULL,30);
INSERT INTO EMP VALUES
(7782,‘CLARK‘,‘MANAGER‘,7839,to_date(‘9-6-1981‘,‘dd-mm-yyyy‘),2450,NULL,10);
INSERT INTO EMP VALUES
(7788,‘SCOTT‘,‘ANALYST‘,7566,to_date(‘13-JUL-87‘)-85,3000,NULL,20);
INSERT INTO EMP VALUES
(7839,‘KING‘,‘PRESIDENT‘,NULL,to_date(‘17-11-1981‘,‘dd-mm-yyyy‘),5000,NULL,10);
INSERT INTO EMP VALUES
(7844,‘TURNER‘,‘SALESMAN‘,7698,to_date(‘8-9-1981‘,‘dd-mm-yyyy‘),1500,0,30);
INSERT INTO EMP VALUES
(7876,‘ADAMS‘,‘CLERK‘,7788,to_date(‘13-JUL-87‘)-51,1100,NULL,20);
INSERT INTO EMP VALUES
(7900,‘JAMES‘,‘CLERK‘,7698,to_date(‘3-12-1981‘,‘dd-mm-yyyy‘),950,NULL,30);
INSERT INTO EMP VALUES
(7902,‘FORD‘,‘ANALYST‘,7566,to_date(‘3-12-1981‘,‘dd-mm-yyyy‘),3000,NULL,20);
INSERT INTO EMP VALUES
(7934,‘MILLER‘,‘CLERK‘,7782,to_date(‘23-1-1982‘,‘dd-mm-yyyy‘),1300,NULL,10);
DROP TABLE BONUS;
CREATE TABLE BONUS
(
ENAME VARCHAR2(10) ,
JOB VARCHAR2(9) ,
SAL NUMBER,
COMM NUMBER
) ;
DROP TABLE SALGRADE;
CREATE TABLE SALGRADE
( GRADE NUMBER,
LOSAL NUMBER,
HISAL NUMBER );
INSERT INTO SALGRADE VALUES (1,700,1200);
INSERT INTO SALGRADE VALUES (2,1201,1400);
INSERT INTO SALGRADE VALUES (3,1401,2000);
INSERT INTO SALGRADE VALUES (4,2001,3000);
INSERT INTO SALGRADE VALUES (5,3001,9999);
COMMIT;
SET TERMOUT ON
SET ECHO ON
然后再执行:
即可。
到此,scott添加成功。
如果需要修改scott用户密码,则执行如下语句:
alter user scott identified by 123456;
怎么样?是不是很简单呢?
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Linux操作系统下oracle数据库中不存在scott用户的解决方案