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LeeCode---Add Two Numbers
You are given two linked lists representing two non-negative numbers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list.
Input: (2 -> 4 -> 3) + (5 -> 6 -> 4)
Output: 7 -> 0 -> 8
/** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; */ class Solution { public: ListNode *addTwoNumbers(ListNode *l1, ListNode *l2) { int In=0; ListNode *pHead=new ListNode(0); ListNode *p=pHead; while(l1!=NULL||l2!=NULL) { int temp1=0; if(l1!=NULL) { temp1=l1->val; l1=l1->next; } int temp2=0; if(l2!=NULL) { temp2=l2->val; l2=l2->next; } int temp=temp1+temp2+In; p->next=new ListNode(temp%10); In=temp/10; p=p->next; } if(In==1) p->next=new ListNode(1); return pHead->next; } };
LeeCode---Add Two Numbers
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