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Python中的字典排序

Python中比较常用的排序有两个函数,

一、定义

(1)一个是List数据结构中的sort

>>> help(list.sort)
Help on method_descriptor:

sort(...)
L.sort(cmp=None, key=None, reverse=False) -- stable sort *IN PLACE*;
cmp(x, y) -> -1, 0, 1

 

  1. The sort() method takes optional arguments for controlling the comparisons.

    cmp specifies a custom comparison function of two arguments (list items) which should return a negative, zero or positive number depending on whether the first argument is considered smaller than, equal to, or larger than the second argument: cmp=lambda x,y: cmp(x.lower(), y.lower()). The default value is None.

    key specifies a function of one argument that is used to extract a comparison key from each list element: key=str.lower. The default value is None.

    reverse is a boolean value. If set to True, then the list elements are sorted as if each comparison were reversed.

    In general, the key and reverse conversion processes are much faster than specifying an equivalent cmp function. This is because cmp is called multiple times for each list element while key and reverse touch each element only once. Use functools.cmp_to_key() to convert an old-style cmp function to a key function.

    Changed in version 2.3: Support for None as an equivalent to omitting cmp was added.

    Changed in version 2.4: Support for key and reverse was added.

 

(2)内置的函数sorted

sorted(iterable[, cmp[, key[, reverse]]])

Return a new sorted list from the items in iterable.

表明内置的sorted函数会生成一个新的数据表不会改变原有数据的顺序。

The optional arguments cmp, key, and reverse have the same meaning as those for the list.sort() method (described in section Mutable Sequence Types).

cmp specifies a custom comparison function of two arguments (iterable elements) which should return a negative, zero or positive number depending on whether the first argument is considered smaller than, equal to, or larger than the second argument: cmp=lambda x,y: cmp(x.lower(), y.lower()). The default value is None.

key specifies a function of one argument that is used to extract a comparison key from each list element: key=str.lower. The default value is None (compare the elements directly).

reverse is a boolean value. If set to True, then the list elements are sorted as if each comparison were reversed.

In general, the key and reverse conversion processes are much faster than specifying an equivalent cmp function. This is because cmp is called multiple times for each list element while key and reverse touch each element only once. Use functools.cmp_to_key() to convert an old-style cmp function to a key function.

 

二、举例

Sorting Basics

>>>sorted([5, 2, 3, 1, 4])[1, 2, 3, 4, 5]

>>> a = [5, 2, 3, 1, 4]>>> a.sort()>>> a[1, 2, 3, 4, 5]

第一种使用的是内置排序方法,第二种是list的排序方法。Usually it‘s less convenient than sorted() - but if you don‘t need the original list, it‘s slightly more efficient.(虽然第一种方法不是很方便,但是通常更有效率)

>>> sorted({1: ‘D‘, 2: ‘B‘, 3: ‘B‘, 4: ‘E‘, 5: ‘A‘})[1, 2, 3, 4, 5]


Another difference is that the list.sort() method is only defined for lists. In contrast, the sorted() function accepts any iterable. 

(另外一点就是list.sort()的方法仅仅只能用作列表的数据结构,然而,sorted却可以用作任何可迭代的数据结构)

 

Key Functions

Starting with Python 2.4, both list.sort() and sorted() added a key parameter to specify a function to be called on each list element prior to making comparisons(从2.4以后,新添加了key参数,通过制定一个判断函数来按照key进行排序)

>>> sorted("This is a test string from Andrew".split(), key=str.lower)[‘a‘, ‘Andrew‘, ‘from‘, ‘is‘, ‘string‘, ‘test‘, ‘This‘]

>>> student_tuples = [        (‘john‘, ‘A‘, 15),        (‘jane‘, ‘B‘, 12),        (‘dave‘, ‘B‘, 10),]>>> sorted(student_tuples, key=lambda student: student[2])   # sort by age[(‘dave‘, ‘B‘, 10), (‘jane‘, ‘B‘, 12), (‘john‘, ‘A‘, 15)]

关于lambda实际上为匿名函数,后面部分会将 lambda 函数参数:返回值


>>> class Student:        def __init__(self, name, grade, age):                self.name = name                self.grade = grade                self.age = age        def __repr__(self):                return repr((self.name, self.grade, self.age))        def weighted_grade(self):                return ‘CBA‘.index(self.grade) / float(self.age) >>> student_objects = [        Student(‘john‘, ‘A‘, 15),        Student(‘jane‘, ‘B‘, 12),        Student(‘dave‘, ‘B‘, 10),]>>> sorted(student_objects, key=lambda student: student.age)   # sort by age[(‘dave‘, ‘B‘, 10), (‘jane‘, ‘B‘, 12), (‘john‘, ‘A‘, 15)]


 
 
 

Python中的字典排序