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Mongoid Without Rails
question
I‘m playing with a standalone ruby application and can‘t configure Mongoid 3.0.13 to work.
I‘ve run across a couple example apps that have configuration blocks like:
Mongoid::Config.instance.from_hash({"database" => "oid"})
Or
Mongoid.configure do |config| name = "mongoid_test_db" host = "localhost" port = 27017 config.database = Mongo::Connection.new.db(name)end
These result in:
undefined method `database=‘ for Mongoid::Config:Module (NoMethodError)
It seems the configuration settings have changed recently.
I also tried:
Mongoid::Config.connect_to("sweet")
But that seems to do nothing.
answer1
By "standalone" I‘m assuming you mean not rails. Mongoid actually provides and easy to make this work regardless of what you‘re running it in.
- Define a
mongoid.yml
file with your database connection info in it like normal. - Make sure you‘ve required Mongoid in your application.
Call
Mongoid.load!
to have Mongoid parse your configuration file and initialize itself.require ‘mongoid‘
Mongoid.load!(‘/path/to/your/mongoid.yml‘)
This info can also be found here under the "Sinatra, Padrino, and others" section: http://mongoid.org/en/mongoid/docs/installation.html
The same approach is applicable for non-webapps. Hope that helps.
answer2
The previous answer is correct to use Mongoid.load! if you want to load from a mongoid config file. I ran into a case where I needed to embed the Mongoid config in another config file. Therefore, I needed a way to load the configuration from a hash.
In >3.1, you will be able to call Mongoid.load_configuration(hash).
Unfortunately, this function is private in 3.0. Therefore, setting up a public alias method before loading Mongoid works:
module Mongoid module Config def load_configuration_hash(settings) load_configuration(settings) end endend
Make sure this code gets called before require ‘mongoid‘. Now you can call Mongoid.load_configuration_hash(hash).
地址: http://stackoverflow.com/questions/15283984/mongoid-without-rails