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xtu字符串 A. Babelfish

2024-07-14 01:26:24   223人阅读

A. Babelfish

Time Limit: 3000ms
Memory Limit: 65536KB
64-bit integer IO format: %lld      Java class name: Main
 
You have just moved from Waterloo to a big city. The people here speak an incomprehensible dialect of a foreign language. Fortunately, you have a dictionary to help you understand them.
 

Input

Input consists of up to 100,000 dictionary entries, followed by a blank line, followed by a message of up to 100,000 words. Each dictionary entry is a line containing an English word, followed by a space and a foreign language word. No foreign word appears more than once in the dictionary. The message is a sequence of words in the foreign language, one word on each line. Each word in the input is a sequence of at most 10 lowercase letters.
 

Output

Output is the message translated to English, one word per line. Foreign words not in the dictionary should be translated as "eh".
 

Sample Input

dog ogdaycat atcaypig igpayfroot ootfrayloops oopslayatcayittenkayoopslay

Sample Output

catehloops

Hint

Huge input and output,scanf and printf are recommended.
 
解题：可以用trie,不过刚学trie，写起来貌似代价很大，而且由于是先读完数据，再查询的，不是动态修改查询的，这种查询折半查找就能完成。
 
先上TLE代码，本来以为STL可以完成的，没想到超时
 
 1 #include <iostream> 2 #include <cstdio> 3 #include <cstring> 4 #include <cstdlib> 5 #include <vector> 6 #include <climits> 7 #include <algorithm> 8 #include <cmath> 9 #include <map>10 #define LL long long11 #define INF 0x3f3f3f12 using namespace std;13 map<string,string>dic;14 char str[200],a[100],b[100],word[100];15 int main(){16     while(gets(str) && str[0] != ‘\0‘){17         sscanf(str,"%s %s",a,b);18         dic.insert(pair<string,string>(b,a));19     }20     map<string,string>::iterator it;21     while(gets(word)){22         if(dic.count(word)) {23             it = dic.find(word);24             printf("%s\n",it->second.c_str());25         }else puts("eh");26     }27     return 0;28 }
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下面是折半查找的代码，速度很快，代码很短，很喜欢呀。。。

 1 #include <iostream> 2 #include <cstdio> 3 #include <cstring> 4 #include <cstdlib> 5 #include <vector> 6 #include <climits> 7 #include <algorithm> 8 #include <cmath> 9 #include <map>10 #define LL long long11 #define INF 0x3f3f3f12 using namespace std;13 struct word {14     char from[20],to[20];15 } dic[100010];16 bool cmp(const word &a,const word &b) {17     if(strcmp(a.from,b.from) <= 0)18         return true;19     return false;20 }21 int bsearch(int lt,int rt,char *str) {22     int mid;23     while(lt <= rt) {24         mid = (lt+rt)>>1;25         if(strcmp(dic[mid].from,str) == 0) return mid;26         if(strcmp(str,dic[mid].from) < 0) rt = mid-1;27         else lt = mid+1;28     }29     return -1;30 }31 int main() {32     int cnt = 0,i,ans;33     char str[50];34     while(gets(str) && str[0] != ‘\0‘) {35         sscanf(str,"%s %s",dic[cnt].to,dic[cnt].from);36         cnt++;37     }38     sort(dic,dic+cnt,cmp);39     while(gets(str)) {40         ans = bsearch(0,cnt,str);41         if(ans == -1) puts("eh");42         else printf("%s\n",dic[ans].to);43     }44     return 0;45 }
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