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C# WinForm 上传图片,文件到服务器的方法Uploader.ashx
网上有很多方案,起初用时,因为对asp.net不太了解,觉得FTP实现不错,可是后来发现,如果机器在域控下,就会有问题。
一年过去了,asp.net也熟悉了,知道ajax没事应该用ashx,验证码也用ashx,当然这里要说的WinForm上传也应该是ashx了吧,哈哈,先提供简单思路:
接收文件的asp.net是:Uploader.ashx,相关代码:
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- <%@ WebHandler Language="C#" Class="Uploader" %>
- using System;
- using System.IO;
- using System.Web;
- public class Uploader : IHttpHandler
- {
- public void ProcessRequest(HttpContext hc)
- {
- foreach (string fileKey in hc.Request.Files)
- {
- HttpPostedFile file = hc.Request.Files[fileKey];
- file.SaveAs(Path.Combine(hc.Server.MapPath("."), file.FileName));
- }
- }
- public bool IsReusable
- {
- get { return true; }
- }
- }
发送图片或文件的WinForm.cs 相关代码:
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- System.Net.WebClient myWebClient = new System.Net.WebClient();
- myWebClient.UploadFile("http://www.yongfa365.com/Uploader.ashx", "POST", "C:\\WINDOWS\\system32\\cmd.exe");
OK,完了,这样操作后,再也不用管是不是在域控内了,只要能上网,就能上传。够方便吧。
如果你要批量上传,还有上传后保存在哪个目录等操作可以参考柳永法(yongfa365)‘Blog写的:
接收文件的asp.net是:Uploader.ashx,相关代码:
view plaincopy to clipboardprint?
- <%@ WebHandler Language="C#" Class="Uploader" %>
- using System;
- using System.IO;
- using System.Web;
- public class Uploader : IHttpHandler
- {
- public void ProcessRequest(HttpContext hc)
- {
- string NowPath = Path.Combine(hc.Server.MapPath("."), hc.Request["path"]);
- if (!Directory.Exists(NowPath))
- {
- Directory.CreateDirectory(NowPath);
- }
- foreach (string fileKey in hc.Request.Files)
- {
- HttpPostedFile file = hc.Request.Files[fileKey];
- string FilePath = Path.Combine(NowPath, file.FileName);
- if (File.Exists(FilePath))
- {
- if (Convert.ToBoolean(hc.Request["overwrite"]))
- {
- File.Delete(FilePath);
- }
- else
- {
- continue;
- }
- }
- file.SaveAs(FilePath);
- }
- }
- public bool IsReusable
- {
- get { return true; }
- }
- }
发送图片或文件的WinForm.cs 相关代码:
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- string url = @"http://www.yongfa365.com/Uploader.ashx?Overwrite=true&PATH=Logs\" + DateTime.Now.ToString("yyyy-MM-dd");
- foreach (string file in Directory.GetFiles(item))
- {
- System.Net.WebClient myWebClient = new System.Net.WebClient();
- myWebClient.UploadFile(url, "POST", file);
- }
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