首页 > 代码库 > Buzz words
Buzz words
给你一个字符串和字典,从头扫到位,如果到当前的字符的字符串存在于字典中,则显示 buzz.
例子:
ILOVEPINEAPPLEJUICE
字典:
[pine, apple, pineapple, juice, applejuice]
那么当我们到达ILOVEPINE的时候,就要buzz,当我们到达APPLE的时候,也要buzz,当我们到达JUICE的时候,也要buzz.
1 public class Solution { 2 3 public static void main(String[] args) { 4 Trie trie = new Trie(); 5 trie.insert("apple"); 6 trie.insert("pie"); 7 trie.insert("applejuice"); 8 trie.insert("juice"); 9 10 Solution s = new Solution(); 11 s.buzz("applepiejuice", trie.root); 12 } 13 14 public void buzz(String str, Node root) { 15 List<Node> list = new ArrayList<Node>(); 16 List<Node> temp = new ArrayList<Node>(); 17 list.add(root); 18 for (int i = 0; i < str.length(); i++) { 19 for (Node node : list) { 20 Node child = node.getChildNode(str.charAt(i)); 21 if (child != null) { 22 temp.add(child); 23 if (child.isEnd) { 24 System.out.println("buzz"); 25 } 26 } 27 } 28 if (i != 0) { 29 Node child = root.getChildNode(str.charAt(i)); 30 if (child != null) { 31 temp.add(child); 32 if (child.isEnd) { 33 System.out.println("buzz"); 34 } 35 } 36 } 37 38 list = temp; 39 temp = new ArrayList<Node>(); 40 } 41 42 } 43 } 44 45 class Trie { 46 Node root; 47 48 public Trie() { 49 root = new Node(‘ ‘); 50 } 51 52 public void insert(String word) { 53 if (exists(word)) 54 return; 55 Node current = root; 56 for (int i = 0; i < word.length(); i++) { 57 char ch = word.charAt(i); 58 Node node = current.getChildNode(ch); 59 if (node == null) { 60 current.map.put(ch, new Node(ch)); 61 current = current.getChildNode(ch); 62 } else { 63 current = node; 64 } 65 } 66 current.isEnd = true; 67 } 68 69 public boolean exists(String word) { 70 Node current = root; 71 for (int i = 0; i < word.length(); i++) { 72 char ch = word.charAt(i); 73 current = current.getChildNode(ch); 74 if (current == null) { 75 return false; 76 } 77 } 78 if (current.isEnd) { 79 return true; 80 } else { 81 return false; 82 } 83 } 84 85 } 86 87 class Node { 88 char ch; 89 boolean isEnd; 90 Map<Character, Node> map; 91 92 public Node(char ch) { 93 this.ch = ch; 94 map = new HashMap<Character, Node>(); 95 } 96 97 public Node getChildNode(char ch) { 98 return map.get(ch); 99 } 100 }
Buzz words
声明:以上内容来自用户投稿及互联网公开渠道收集整理发布,本网站不拥有所有权,未作人工编辑处理,也不承担相关法律责任,若内容有误或涉及侵权可进行投诉: 投诉/举报 工作人员会在5个工作日内联系你,一经查实,本站将立刻删除涉嫌侵权内容。