简单题，公式计算+最短路。注意点：注意1 取模，2 数组开到n*n+n.

#include<iostream>
#include<queue>
using namespace std;
long long x[1234567];long long y[1234567];long long z[1234567]; 
int c[1001][1001];
int d[1002];int inq[1002];
const int inf=0x3f3f3f3f;
int n,m;
void spfa()
{
    for(int i=0;i<n;i++)
    {
        d[i]=inf;inq[i]=0;
    }
    queue<int>q;
    inq[0]=1;d[0]=0;
    q.push(0);
    while(!q.empty())
    {
        int cur=q.front();
        q.pop();inq[cur]=0;
        for(int i=0;i<n;i++)
        {
            if(d[i]>c[cur][i]+d[cur])
            {
               d[i]=c[cur][i]+d[cur];
               if(!inq[i])
               {
                   q.push(i);
                   inq[i]=1;
               }
            }
        }
    }
}
int main()
{
    while(cin>>n>>m>>x[0]>>x[1]>>y[0]>>y[1])
    {
        for(int i=2;i<(n-1)*n+n;i++)
        {
            x[i]=(12345+x[i-1]*23456%5837501+x[i-2]*34567%5837501+x[i-1]*x[i-2]%5837501*45678%5837501)%5837501;
            y[i]=(56789+y[i-1]*67890%9860381+y[i-2]*78901%9860381+y[i-1]*y[i-2]%9860381*89012%9860381)%9860381;
        }
        for(int k=0;k<(n-1)*n+n;k++)
        {
            z[k]= (x[k]*90123%8475871+y[k])%8475871+1;
        }
        for(int i=0;i<n;i++)
          for(int j=0;j<n;j++)
          {
              if(i==j)
              {
                  c[i][j]=0;
              }
              else
              {
                  c[i][j]= z[i*n+j];
              }
          }
            spfa();
          int minn=d[1]%m;
        for(int i=2;i<n;i++)
        {
            if(d[i]%m<minn)
            {
                minn=d[i]%m;
            }
        }
        cout<<minn<<endl;
    }
}