首页 > 代码库 > LeetCode:Best Time to Buy and Sell Stock II
LeetCode:Best Time to Buy and Sell Stock II
Say you have an array for which the ith element is the price of a given stock on day i.
Design an algorithm to find the maximum profit. You may complete as many transactions as you like (ie, buy one and sell one share of the stock multiple times). However, you may not engage in multiple transactions at the same time (ie, you must sell the stock before you buy again).
思路如下：
找到所有价格的递增区间，每个区间内以对低价买入最高价卖出
1 class Solution{ 2 public: 3 int maxProfit(vector<int> &prices){ 4 int len=prices.size(); 5 if(len<=1) 6 { 7 return 0; 8 } 9 int max=0,i=0;10 while(i<len-1)11 {12 int buy,sell;13 while(i<len-1&&prices[i+1]<prices[i])i++;14 buy=i++;15 while(i<len&&prices[i]>prices[i-1])i++;16 sell=i-1;17 max+=prices[sell]-prices[buy];18 }19 return max;20 }21 };
LeetCode:Best Time to Buy and Sell Stock II
声明：以上内容来自用户投稿及互联网公开渠道收集整理发布，本网站不拥有所有权，未作人工编辑处理，也不承担相关法律责任，若内容有误或涉及侵权可进行投诉： 投诉/举报 工作人员会在5个工作日内联系你，一经查实，本站将立刻删除涉嫌侵权内容。