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2. Add Two Numbers

You are given two linked lists representing two non-negative numbers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list.

Input: (2 -> 4 -> 3) + (5 -> 6 -> 4)
Output: 7 -> 0 -> 8

time complexity O(n)
space complexity O(1)

  1. /**
  2. * Definition for singly-linked list.
  3. * struct ListNode {
  4. * int val;
  5. * ListNode *next;
  6. * ListNode(int x) : val(x), next(NULL) {}
  7. * };
  8. */
  9. class Solution {
  10. public:
  11. ListNode* addTwoNumbers(ListNode* l1, ListNode* l2) {
  12. ListNode * pHead = new ListNode(0);
  13. ListNode * pi = pHead;
  14. int carry = 0;
  15. while( l1 != NULL || l2 != NULL){
  16. int sum = (l1==NULL?0:l1->val) + (l2==NULL?0:l2->val) + carry;
  17. carry = sum / 10;
  18. pi->next = new ListNode(sum%10);
  19. pi = pi->next;
  20. if( l1 != NULL)l1 = l1->next;
  21. if( l2 != NULL)l2 = l2->next;
  22. }
  23. if(carry == 1)
  24. pi->next = new ListNode(carry);
  25. return pHead->next;
  26. }
  27. };



来自为知笔记(Wiz)


2. Add Two Numbers