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2. Add Two Numbers
You are given two linked lists representing two non-negative numbers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list.
Input: (2 -> 4 -> 3) + (5 -> 6 -> 4)
Output: 7 -> 0 -> 8
time complexity O(n)
space complexity O(1)
/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode(int x) : val(x), next(NULL) {}
* };
*/
class Solution {
public:
ListNode* addTwoNumbers(ListNode* l1, ListNode* l2) {
ListNode * pHead = new ListNode(0);
ListNode * pi = pHead;
int carry = 0;
while( l1 != NULL || l2 != NULL){
int sum = (l1==NULL?0:l1->val) + (l2==NULL?0:l2->val) + carry;
carry = sum / 10;
pi->next = new ListNode(sum%10);
pi = pi->next;
if( l1 != NULL)l1 = l1->next;
if( l2 != NULL)l2 = l2->next;
}
if(carry == 1)
pi->next = new ListNode(carry);
return pHead->next;
}
};
来自为知笔记(Wiz)
2. Add Two Numbers
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