首页 > 代码库 > [leetcode]Single Number

[leetcode]Single Number

Single Number

Given an array of integers, every element appears twice except for one. Find that single one.

Note:
Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory?

算法思路:

抑或^满足交换律和结合律

交换律: a ^ b ^ c ^ d = a ^ d ^ b ^ c;

结合律: a ^ b ^ c ^ d = a ^ (d ^ b) ^ c;

相同数字 a ^ a = 0

代码如下:

1 public class Solution {2     public int singleNumber(int[] a) {3         int res = 0;4         for(int tem : a){5             res ^= tem;6         }7         return res;8     }9 }