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[leetcode]Single Number
Single Number
Given an array of integers, every element appears twice except for one. Find that single one.
Note:
Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory?
算法思路:
抑或^满足交换律和结合律
交换律: a ^ b ^ c ^ d = a ^ d ^ b ^ c;
结合律: a ^ b ^ c ^ d = a ^ (d ^ b) ^ c;
相同数字 a ^ a = 0
代码如下:
1 public class Solution {2 public int singleNumber(int[] a) {3 int res = 0;4 for(int tem : a){5 res ^= tem;6 }7 return res;8 }9 }
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