首页 > 代码库 > poj1552
poj1552
Doubles
Time Limit: 1000MS | Memory Limit: 10000K | |
Total Submissions: 19154 | Accepted: 11064 |
Description
As part of an arithmetic competency program, your students will be given randomly generated lists of from 2 to 15 unique positive integers and asked to determine how many items in each list are twice some other item in the same list. You will need a program to help you with the grading. This program should be able to scan the lists and output the correct answer for each one. For example, given the list
your program should answer 3, as 2 is twice 1, 4 is twice 2, and 18 is twice 9.
1 4 3 2 9 7 18 22
your program should answer 3, as 2 is twice 1, 4 is twice 2, and 18 is twice 9.
Input
The input will consist of one or more lists of numbers. There will be one list of numbers per line. Each list will contain from 2 to 15 unique positive integers. No integer will be larger than 99. Each line will be terminated with the integer 0, which is not considered part of the list. A line with the single number -1 will mark the end of the file. The example input below shows 3 separate lists. Some lists may not contain any doubles.
Output
The output will consist of one line per input list, containing a count of the items that are double some other item.
Sample Input
1 4 3 2 9 7 18 22 02 4 8 10 07 5 11 13 1 3 0-1
Sample Output
320
Source
Mid-Central USA 2003
1 #include <iostream> 2 #include<cstring> 3 using namespace std; 4 5 int main() 6 { 7 int a[20]; 8 cin>>a[0]; 9 while(a[0]!=-1)10 {11 int n =1;12 int ans = 0;13 for(;;n++)14 {15 cin>>a[n];16 if(a[n]==0)17 break;18 }19 for(int i=0;i<n-1;i++)20 {21 for(int j=i+1;j<n;j++)22 if(a[i]*2==a[j]||a[i]==a[j]*2)23 ans++;24 }25 cout<<ans<<endl;26 memset(a,0,sizeof(a));27 cin>>a[0];28 }29 return 0;30 }
声明:以上内容来自用户投稿及互联网公开渠道收集整理发布,本网站不拥有所有权,未作人工编辑处理,也不承担相关法律责任,若内容有误或涉及侵权可进行投诉: 投诉/举报 工作人员会在5个工作日内联系你,一经查实,本站将立刻删除涉嫌侵权内容。