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python整合连续数字的练习，包含itertools\groupby用法

2024-07-16 22:57:27   220人阅读

#汉字数字转阿拉伯数字
 1 class ConvertNum: 2     def __init__(self,cnNum): 3     　　self.dict =   {u‘零‘:0,u‘一‘:1,u‘二‘:2,u‘三‘:3,u‘四‘:4,u‘五‘:5,u‘六‘:6,u‘七‘:7,u‘八‘:8,u‘九‘:9,u‘十‘:10,u‘百‘:100,u‘千‘:1000,u‘万‘:10000} 4     　　self.cnNum = cnNum 5  6     def convert(self): 7         count = 0 8         result = 0 9         tmp = 010 11         while count < len(self.cnNum):12         tmpChr = self.cnNum[count:count+1]13         tmpNum = self.dict[tmpChr]14 15         if tmpNum == 10000:16             result = result + tmp17             result = result * tmpNum18         elif tmpNum >= 10:19             if tmp==0:20             　　tmp = 121             result = result + tmpNum * tmp22             tmp = 023         else:24             tmp = tmpNum25             count = count + 126             result = result + tmp27         return result                    
 1 import re 2 from convertNum import ConvertNum 3 from itertools import *
 4 list_a = [u‘中华一村‘,u‘中华二村‘,u‘中华三村‘,u‘中华十二村‘,u‘中华五村‘,u‘中点开‘,u‘大地三街‘,u‘大地二街‘,u‘中华七村‘,u‘中华八村‘,u‘中华九村‘] 6     patternCombineHz = re.compile(ur‘(.*?)([一二三四五六七八九十]+)([村街巷连])$‘) 7     l,dicts = [],[] 8     for item in list_a: 9         m = patternCombineHz.search(item)     #获取数字信息10         if m:11             dict = {‘headFootText‘:(m.group(1),m.group(3)),‘numText‘:m.group(2)}12             dicts.append(dict)13         else:14             l.append(item)15     dictHead = {}16     for dict in dicts:     #生成头尾为key，数字为value的字典17         if dictHead.has_key(dict.get(‘headFootText‘)):18             dictHead[dict.get(‘headFootText‘)].append(dict.get(‘numText‘))19         else:20             dictHead[dict.get(‘headFootText‘)] = [dict.get(‘numText‘)]21     for key,value in dictHead.items():22         dictNum = {}23         for i in value:24             dictNum[ConvertNum(i).convert()] = i25         sortalbNum = sorted([ConvertNum(i).convert() for i in value])   #汉字转换阿拉伯数字后排序26         newNum = []27         #排序后列表元素减去索引号，判断是否等差，并分组生成迭代器，每一组表示连续数字28         for k,g in groupby(enumerate(sortalbNum),lambda (i,x):x-i):29             gb = [t[1] for t in g]30             mingb,maxgb = min(gb),max(gb)31             if maxgb-mingb>1:32                 combineStr = u‘~‘.join(map(lambda num:dictNum.get(num),[mingb,maxgb]))33                 newNum.append(combineStr)34             else:35                 newNum.extend(map(lambda num:dictNum.get(num),gb))36         # newNum = [dictNum.get(num) for num in sortalbNum]37         if len(newNum) == 1 and not u‘~‘ in newNum[0]:38             combineAddr = u‘%s%s%s‘ % (key[0],u‘、‘.join(newNum),key[1])39         else:40             combineAddr = u‘%s（%s）%s‘ % (key[0],u‘、‘.join(newNum),key[1])41         l.append(combineAddr)42 43     for i in l:44         print i

output:>>>>>>>>

中点开
中华（一~三、五、七~九、十二）村
大地（二、三）街


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