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ZOJ 3471 Most Powerful 状压DP

水题,一维的DP,表示还剩哪些atom的时候能获得的最大能量

 

#include <cstdio>#include <cstring>#include <iostream>#include <map>#include <set>#include <vector>#include <string>#include <queue>#include <deque>#include <bitset>#include <list>#include <cstdlib>#include <climits>#include <cmath>#include <ctime>#include <algorithm>#include <stack>#include <sstream>#include <numeric>#include <fstream>#include <functional>using namespace std;#define MP make_pair#define PB push_backtypedef long long LL;typedef unsigned long long ULL;typedef vector<int> VI;typedef pair<int,int> pii;const int INF = INT_MAX / 3;const double eps = 1e-8;const LL LINF = 1e17;const double DINF = 1e60;const int maxn = 15;int dist[maxn][maxn],n,f[1 << 11];int dfs(int state) {    int ret = 0;    if(~f[state]) return f[state];    for(int i = 0;i < n;i++) if(state & (1 << i)) {        for(int j = 0;j < n;j++) if(state & (1 << j)) {            if(i == j) continue;            ret = max(ret,dfs(state & (~(1 << j))) + dist[i][j]);        }    }    return f[state] = ret;}int main() {    while(scanf("%d",&n),n) {        for(int i = 0;i < n;i++) {            for(int j = 0;j < n;j++) {                scanf("%d",&dist[i][j]);            }        }        memset(f,-1,sizeof(f));        int ans = dfs((1 << n) - 1);        printf("%d\n",ans);    }    return 0;}